Test of u = 20.22 vs u > 20.22 The assumed standard deviation = 0.08 Sample Sample Standard size mean error SE n 20.31 0.03578 Complete the analysis by calculating the value of the one-sample z-statistic, the p-value, and making the decision. Firs calculate z to at least two decimal places.

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Find Z.

Test of µ = 20.22 vs µ > 20.22
The assumed standard deviation = 0.08
Sample
Sample
Standard
size
mean
error
SE
20.31
0.03578
Complete the analysis by calculating the value of the one-sample z-statistic, the p-value, and making the decision. Firs
calculate z to at least two decimal places.
ofuse contact us
heip
privacy poilcy
labout Us
11/
自 回
hp
%3D
Transcribed Image Text:Test of µ = 20.22 vs µ > 20.22 The assumed standard deviation = 0.08 Sample Sample Standard size mean error SE 20.31 0.03578 Complete the analysis by calculating the value of the one-sample z-statistic, the p-value, and making the decision. Firs calculate z to at least two decimal places. ofuse contact us heip privacy poilcy labout Us 11/ 自 回 hp %3D
Attempt 4
The National Institute of Standards and Technology (NIST) offers Standard Reference Materials to aid in the calibration of
measurement instruments and verify the accuracy of measurements. Suppose a medical researcher wants to verify that the
distances he measures with his computed tomography machine are not too large, so he orders a Dimensional Standard for
Medical Computed Tomography from NIST.
This standard consists of 18 plastic balls held in place by a plastic support structure. The certified distance between the balls
numbered 3 and 5 is 20.22 mm, and NIST determines that measurement errors are normally distributed with a standard
deviation of 0.08 mm. Upon receiving the Standard Reference Material, the researcher measured the distance between balls 3
and 5 five times. Take these five measurements to be a simple random sample of all measurements made on this device under
carefully controlled conditions. The researcher then calculated the summary statistics, where u is the mean distance between
balls 3 and 5, as measured by his computed tomography machine.
Test of u = 20.22 vs u > 20.22
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help
6:44 PM
11/27/2020
a
2.
hp
prt sc
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Transcribed Image Text:Attempt 4 The National Institute of Standards and Technology (NIST) offers Standard Reference Materials to aid in the calibration of measurement instruments and verify the accuracy of measurements. Suppose a medical researcher wants to verify that the distances he measures with his computed tomography machine are not too large, so he orders a Dimensional Standard for Medical Computed Tomography from NIST. This standard consists of 18 plastic balls held in place by a plastic support structure. The certified distance between the balls numbered 3 and 5 is 20.22 mm, and NIST determines that measurement errors are normally distributed with a standard deviation of 0.08 mm. Upon receiving the Standard Reference Material, the researcher measured the distance between balls 3 and 5 five times. Take these five measurements to be a simple random sample of all measurements made on this device under carefully controlled conditions. The researcher then calculated the summary statistics, where u is the mean distance between balls 3 and 5, as measured by his computed tomography machine. Test of u = 20.22 vs u > 20.22 terms of use contact us help 6:44 PM 11/27/2020 a 2. hp prt sc insert
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