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tert-Butyl alcohol is a solvent with a Kf of 9.10 °C/m and a freezing point of 25.5°C. When 0.807 g of an upknown colorless nonelectrolyte liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 °C.Which of the following is most likely the identity of this unknown liquid? > View Available Hint(s) O ethylene glycol (molar mass = 62.07 g/mol) O 1-octanol (molar mass = 130.22 g/mol) O glycerol (molar mass = 92.09 g/mol) %3D O 2-pentanone (molar mass = 86.13 g/mol) O 1-butanol (molar mass = 74.12 g/mol) Submit

tert-Butyl alcohol is a solvent with a Kf of 9.10 °C/m and a freezing point of 25.5°C. When 0.807 g of an upknown colorless nonelectrolyte liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 °C.Which of the following is most likely the identity of this unknown liquid? > View Available Hint(s) O ethylene glycol (molar mass = 62.07 g/mol) O 1-octanol (molar mass = 130.22 g/mol) O glycerol (molar mass = 92.09 g/mol) %3D O 2-pentanone (molar mass = 86.13 g/mol) O 1-butanol (molar mass = 74.12 g/mol) Submit

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I Review | Constants | Periodic Table The molar mass of a compound expresses the ratio of mass to moles: mass in grams Part A molar mass = number of moles tert-Butyl alcohol is a solvent with a K¡ of 9.10 °C/m and a freezing point of 25.5 °C. When 0.807 g of an upknown colorless nonelectrolyte liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 C.Which of the following is most likely the identity of this unknown liquid? This quantity can be determined experimentally by accurately measuring the mass of the sample and determining the corresponding number of moles based on some property of the sample. Freezing- point depression and osmotic pressure measurements are frequently used to calculate the number of moles in solution for this type of determination. > View Available Hint(s) O ethylene glycol (molar mass = 62.07 g/mol) %3D Freezing-point depression is equal to O 1-octanol (molar mass = 130.22 g/mol) %3D AT = Kt m O glycerol (molar mass = 92.09 g/mol) where AT is the change in temperature, KĘ is the molal freezing-point-depression constant, and m is the molality in moles of solute per mass of solvent. O 2-pentanone (molar mass = 86.13 g/mol) %3D O 1-butanol (molar mass = 74.12 g/mol) Osmotic pressure is equal to II = MRT Submit where II is the osmotic pressure, R=0.08206 L - atm/(K mol),T is temperature, and M is molarity in moles per liter of solution. !! Part B A protein subunit from an enzyme is part of a research study and needs to be characterized.A total of 0.135 g of this subunit was dissolved in enough water to produce 2.00 mL of solution. At 28 ° C the osmotic pressure produced by the solution was 0.138 atm. What is the molar mass of the protein? Express your answer with the appropriate units. > View Available Hint(s) HA ?
Transcribed Image Text:I Review | Constants | Periodic Table The molar mass of a compound expresses the ratio of mass to moles: mass in grams Part A molar mass = number of moles tert-Butyl alcohol is a solvent with a K¡ of 9.10 °C/m and a freezing point of 25.5 °C. When 0.807 g of an upknown colorless nonelectrolyte liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 C.Which of the following is most likely the identity of this unknown liquid? This quantity can be determined experimentally by accurately measuring the mass of the sample and determining the corresponding number of moles based on some property of the sample. Freezing- point depression and osmotic pressure measurements are frequently used to calculate the number of moles in solution for this type of determination. > View Available Hint(s) O ethylene glycol (molar mass = 62.07 g/mol) %3D Freezing-point depression is equal to O 1-octanol (molar mass = 130.22 g/mol) %3D AT = Kt m O glycerol (molar mass = 92.09 g/mol) where AT is the change in temperature, KĘ is the molal freezing-point-depression constant, and m is the molality in moles of solute per mass of solvent. O 2-pentanone (molar mass = 86.13 g/mol) %3D O 1-butanol (molar mass = 74.12 g/mol) Osmotic pressure is equal to II = MRT Submit where II is the osmotic pressure, R=0.08206 L - atm/(K mol),T is temperature, and M is molarity in moles per liter of solution. !! Part B A protein subunit from an enzyme is part of a research study and needs to be characterized.A total of 0.135 g of this subunit was dissolved in enough water to produce 2.00 mL of solution. At 28 ° C the osmotic pressure produced by the solution was 0.138 atm. What is the molar mass of the protein? Express your answer with the appropriate units. > View Available Hint(s) HA ?
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