terms of 7. 9. 1.7 ft 10. See Problem in. WIN

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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find the area in terms of pi and answer both questions separately they're two parts in one question. 

### Finding the Area of a Circle

To calculate the area of a circle, use the following formula:

\[ \text{Area} = \pi r^2 \]

Where:
- \( \pi \) is a constant (approximately 3.14159)
- \( r \) is the radius of the circle

### Example Problems

#### Problem 9:
A circle with a diameter labeled as **1.7 feet**.

**Solution:**
1. First, find the radius. The radius \( r \) is half of the diameter.
   \[ r = \frac{1.7 \text{ ft}}{2} = 0.85 \text{ ft} \]
2. Then use the formula to find the area.
   \[ \text{Area} = \pi (0.85 \text{ ft})^2 \]
   \[ \text{Area} = \pi (0.7225) \text{ ft}^2 \]
   \[ \text{Area} \approx 2.27 \pi \text{ ft}^2 \]

#### Problem 10:
A circle with a diameter labeled as \( \frac{2}{3} \) inches.

**Solution:**
1. First, find the radius. The radius \( r \) is half of the diameter.
   \[ r = \frac{\frac{2}{3} \text{ in}}{2} = \frac{1}{3} \text{ in} \]
2. Then use the formula to find the area.
   \[ \text{Area} = \pi \left( \frac{1}{3} \text{ in} \right)^2 \]
   \[ \text{Area} = \pi \left( \frac{1}{9} \right) \text{ in}^2 \]
   \[ \text{Area} = \frac{\pi}{9} \text{ in}^2 \]

### Diagrams Explanation

**Diagram 9:**
- A circle with a diameter measuring 1.7 feet is shown. This requires computing the radius as half of the diameter to then find the area using the area formula.

**Diagram 10:**
- A circle with a diameter measuring \( \frac{2}{3} \) inches is displayed. Similarly, the radius is determined by halving the diameter
Transcribed Image Text:### Finding the Area of a Circle To calculate the area of a circle, use the following formula: \[ \text{Area} = \pi r^2 \] Where: - \( \pi \) is a constant (approximately 3.14159) - \( r \) is the radius of the circle ### Example Problems #### Problem 9: A circle with a diameter labeled as **1.7 feet**. **Solution:** 1. First, find the radius. The radius \( r \) is half of the diameter. \[ r = \frac{1.7 \text{ ft}}{2} = 0.85 \text{ ft} \] 2. Then use the formula to find the area. \[ \text{Area} = \pi (0.85 \text{ ft})^2 \] \[ \text{Area} = \pi (0.7225) \text{ ft}^2 \] \[ \text{Area} \approx 2.27 \pi \text{ ft}^2 \] #### Problem 10: A circle with a diameter labeled as \( \frac{2}{3} \) inches. **Solution:** 1. First, find the radius. The radius \( r \) is half of the diameter. \[ r = \frac{\frac{2}{3} \text{ in}}{2} = \frac{1}{3} \text{ in} \] 2. Then use the formula to find the area. \[ \text{Area} = \pi \left( \frac{1}{3} \text{ in} \right)^2 \] \[ \text{Area} = \pi \left( \frac{1}{9} \right) \text{ in}^2 \] \[ \text{Area} = \frac{\pi}{9} \text{ in}^2 \] ### Diagrams Explanation **Diagram 9:** - A circle with a diameter measuring 1.7 feet is shown. This requires computing the radius as half of the diameter to then find the area using the area formula. **Diagram 10:** - A circle with a diameter measuring \( \frac{2}{3} \) inches is displayed. Similarly, the radius is determined by halving the diameter
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