ter Exercise 2: Solve the following recurrence relation: a) an+1 = dan + c , ao = 0 %3D antant n-2 . ナリく az=dctC=(dtoc az=(d+udc+c =(d+d}+()c a4=0'+d+1) defc dcrc %3D au=(13+d<4dri)c b) až+1 = 2a% ,ao = 5 %3D %3D c) F = 5Fn-1 – 6Fn-2 , Fo = 1 and F, = 4 %3D %3D Gr-3)6-2)=0 rこ3,2 r(r-3)-2(r-3)=0 r?_3r-2rto20 Fnこと(3"+212) Fo>1 = Kitk2 3と」けと2

ter Exercise 2: Solve the following recurrence relation: a) an+1 = dan + c , ao = 0 %3D antant n-2 . ナリく az=dctC=(dtoc az=(d+udc+c =(d+d}+()c a4=0'+d+1) defc dcrc %3D au=(13+d<4dri)c b) až+1 = 2a% ,ao = 5 %3D %3D c) F = 5Fn-1 – 6Fn-2 , Fo = 1 and F, = 4 %3D %3D Gr-3)6-2)=0 rこ3,2 r(r-3)-2(r-3)=0 r?_3r-2rto20 Fnこと(3"+212) Fo>1 = Kitk2 3と」けと2

Name: Discrete mathematics/structures terExercise 2: Solve the following rec
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Description: Discrete mathematics/structures terExercise 2: Solve the following recurrence relation:a) an+1 = dan + c , ao = 0%3Dantantn-2. ナリくaz=dctC=(dtocaz=(d+udc+c =(d+d}+()ca4=0'+d+1) defcdcrc%3Dau=(13+d<4dri)cb) až+1 = 2a% ,ao = 5%3D%3Dc) F = 5Fn-1 – 6Fn-2

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Discrete mathematics/structures

ter
Exercise 2: Solve the following recurrence relation:
a) an+1 = dan + c , ao = 0
%3D
antant
n-2
. ナリく
az=dctC=(dtoc
az=(d+udc+c =(d+d}+()c
a4=0'+d+1) defc
dcrc
%3D
au=(13+d<4dri)c
b) až+1 = 2a% ,ao = 5
%3D
%3D
c) F = 5Fn-1 – 6Fn-2 , Fo = 1 and F, = 4
%3D
%3D
Gr-3)6-2)=0 rこ3,2
r(r-3)-2(r-3)=0
r?_3r-2rto20
Fnこと(3"+212) Fo>1 = Kitk2
3と」けと2

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