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tep 4 After integration by parts we have cos(40) de = e38 sin(40) de-

tep 4 After integration by parts we have cos(40) de = e38 sin(40) de-

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Evaluate the integral. e30 sin(48) de Step 1 We will begin by letting u = sin(48) and dv = e39 de. Then du = sin 40 4 cos(46)| 1 de and v = 3 Step 2 After integration by parts we have sin( 40)e30 4/3 | e39 cos(40) de- 1 4/3 30 sin(40) e39 sin(48) de = 3 Step 3 We'll now apply the integration by parts procedure to the new integral / e39 cos(48) de, letting u = cos(40) and dV = e38 de. 30 30 Then du = -4 sin(40) -4 sin(40)| de and V = 3 3 Step 4 After integration by parts we have e3* cos(40) de sin(40) de.
Transcribed Image Text:Evaluate the integral. e30 sin(48) de Step 1 We will begin by letting u = sin(48) and dv = e39 de. Then du = sin 40 4 cos(46)| 1 de and v = 3 Step 2 After integration by parts we have sin( 40)e30 4/3 | e39 cos(40) de- 1 4/3 30 sin(40) e39 sin(48) de = 3 Step 3 We'll now apply the integration by parts procedure to the new integral / e39 cos(48) de, letting u = cos(40) and dV = e38 de. 30 30 Then du = -4 sin(40) -4 sin(40)| de and V = 3 3 Step 4 After integration by parts we have e3* cos(40) de sin(40) de.
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