Tell the maximum number of zeros that the polynomial function may have. Then use Descartes' Rule of Signs to determine how many positive and how many negative zeros the polynomial function may have. Do not attempt to find the zeros. f(x) = 3x -x2 +x+8 What is the maximum number of zeros this polynomial function can have?

College Algebra (MindTap Course List)
12th Edition
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Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.2: Polynomial Functions
Problem 90E
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### Polynomial Zeros Calculation

**Objective:**
Determine the maximum number of zeros that the polynomial function may have. Then, utilize Descartes' Rule of Signs to ascertain the number of positive and negative zeros the polynomial function may possess. Do not attempt to find the zeros.

**Given Polynomial Function:**
\[ f(x) = 3x^3 - x^2 + x + 8 \]

**Step-by-Step Instructions:**

1. **Maximum Number of Zeros:**
   The maximum number of zeros a polynomial function can have is equal to its degree. For the given polynomial \( f(x) = 3x^3 - x^2 + x + 8 \), the degree is 3. Therefore, the maximum number of zeros is 3.

2. **Descartes' Rule of Signs:**
   - **Positive Zeros:**
     Count the number of sign changes in \( f(x) = 3x^3 - x^2 + x + 8 \).
     \[
     \begin{align*}
     3x^3 & \quad (- \text{sign change}) \\
     - x^2 & \quad (+ \text{sign change}) \\
     + x & \quad (+ \text{no sign change}) \\
     + 8
     \end{align*}
     \]
     There are 2 sign changes, implying there could be 2 or 0 positive zeros.

   - **Negative Zeros:**
     To find the negative zeros, evaluate \( f(-x) \).
     \[
     f(-x) = 3(-x)^3 - (-x)^2 + (-x) + 8 = -3x^3 - x^2 - x + 8
     \]
     Count the number of sign changes in \( f(-x) \).
     \[
     \begin{align*}
     -3x^3 & \quad (- \text{no sign change}) \\
     - x^2 & \quad (- \text{no sign change}) \\
     - x & \quad (+ \text{sign change}) \\
     + 8
     \end{align*}
     \]
     There is 1 sign change, implying there could be 1 or 0 negative zeros.

**Question:**
What is the maximum number of zeros this polynomial function can
Transcribed Image Text:### Polynomial Zeros Calculation **Objective:** Determine the maximum number of zeros that the polynomial function may have. Then, utilize Descartes' Rule of Signs to ascertain the number of positive and negative zeros the polynomial function may possess. Do not attempt to find the zeros. **Given Polynomial Function:** \[ f(x) = 3x^3 - x^2 + x + 8 \] **Step-by-Step Instructions:** 1. **Maximum Number of Zeros:** The maximum number of zeros a polynomial function can have is equal to its degree. For the given polynomial \( f(x) = 3x^3 - x^2 + x + 8 \), the degree is 3. Therefore, the maximum number of zeros is 3. 2. **Descartes' Rule of Signs:** - **Positive Zeros:** Count the number of sign changes in \( f(x) = 3x^3 - x^2 + x + 8 \). \[ \begin{align*} 3x^3 & \quad (- \text{sign change}) \\ - x^2 & \quad (+ \text{sign change}) \\ + x & \quad (+ \text{no sign change}) \\ + 8 \end{align*} \] There are 2 sign changes, implying there could be 2 or 0 positive zeros. - **Negative Zeros:** To find the negative zeros, evaluate \( f(-x) \). \[ f(-x) = 3(-x)^3 - (-x)^2 + (-x) + 8 = -3x^3 - x^2 - x + 8 \] Count the number of sign changes in \( f(-x) \). \[ \begin{align*} -3x^3 & \quad (- \text{no sign change}) \\ - x^2 & \quad (- \text{no sign change}) \\ - x & \quad (+ \text{sign change}) \\ + 8 \end{align*} \] There is 1 sign change, implying there could be 1 or 0 negative zeros. **Question:** What is the maximum number of zeros this polynomial function can
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