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Technetium-99m (gamma emitter, t1/2 = 6.02 hr) is widely used for diagnosis in medicine. A sample prepared in the early morning for use that day had an activity of 4.52 × 10-6 Ci. What will its activity be at the end of the day-that is, after 8.00 hr?

Technetium-99m (gamma emitter, t1/2 = 6.02 hr) is widely used for diagnosis in medicine. A sample prepared in the early morning for use that day had an activity of 4.52 × 10-6 Ci. What will its activity be at the end of the day-that is, after 8.00 hr?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Technetium-99m (gamma emitter, t1/2 = 6.02 hr) is widely used for diagnosis in medicine. A sample prepared in the early morning for use that day had an activity of 4.52 × 10-6 Ci.

What will its activity be at the end of the day-that is, after 8.00 hr?

Technetium-99m (gamma emitter, t1/2 = 6.02 hr) is widely used for diagnosis in medicine. A sample prepared in the early morning for use that day had an activity of 4.52 x 106 Ci. Part 1 Your answer is correct. Choose the equations needed to calculate the activity. |In ([A]o[A]) = kt O In ([A]MA]) = kt O k= t1/2 In2 V k= In2 /t1/2 eTextbook and Media Attempts: 1 of 15 used Part 2 What will its activity be at the end of the day-that is, after 8.00 hr? [A]: - i Ci
Transcribed Image Text:Technetium-99m (gamma emitter, t1/2 = 6.02 hr) is widely used for diagnosis in medicine. A sample prepared in the early morning for use that day had an activity of 4.52 x 106 Ci. Part 1 Your answer is correct. Choose the equations needed to calculate the activity. |In ([A]o[A]) = kt O In ([A]MA]) = kt O k= t1/2 In2 V k= In2 /t1/2 eTextbook and Media Attempts: 1 of 15 used Part 2 What will its activity be at the end of the day-that is, after 8.00 hr? [A]: - i Ci
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