Team A has won two games and team B has won none in a best-of-five series. The first team to win three games wins the series and tie games are not allowed. If team A has a 60% chance of winning each game, what is the probability team A will win the series? ) 0.600 a) 0.936 b) 0400 g) none of the others c) 0.500 d) Q784 e) 0.875

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Problem EXPLANATION needed! I have the key and I already know the answer is A. But I need an explanation!

14 Team A has won two games and team B has won none in a best-of-five series. The first team
to win three games wins the series and tie games are not allowed. If team A has a 60%
chance of winning each game, what is the probability team A will win the series?
a) 0.936
g) none of the others
c) 0.500
Đ 0.600
b) 0.400
d) a784
e) 0.875
Transcribed Image Text:14 Team A has won two games and team B has won none in a best-of-five series. The first team to win three games wins the series and tie games are not allowed. If team A has a 60% chance of winning each game, what is the probability team A will win the series? a) 0.936 g) none of the others c) 0.500 Đ 0.600 b) 0.400 d) a784 e) 0.875
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