te approximation:

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A thin rod lies on the z-axis with one end at - A and the other end at A, as shown in the diagram. A charge of Q is spread uniformly over
the surface of the rod. We want to set up an integral to find the electric field at location < 0, y, 0> due to the rod. Following the
procedure discussed in the textbook, we have cut up the rod into small segments, each of which can be considered as a point charge. We
have selected a typical piece, shown in red on the diagram.
* Your answer is incorrect.
For a disk of radius R = 22 cm and Q = 4x 106 C, calculate the electric field 2 cm from the center of the disk using all three
formulas below, and using the accurate value 0 = 8.85 x 10-12 C²/(N-m²).
(a) most accurate approximation: E =
135169007.8
(b) less accurate approximation: E =
135113519.5
N/C
148624871.4
N/C
(c) least accurate approximation: E =
QIA
200
QIA
200
[1-
QIA
20
-
1/2
(R² +2²) ¹¹/²
Ē
Transcribed Image Text:A thin rod lies on the z-axis with one end at - A and the other end at A, as shown in the diagram. A charge of Q is spread uniformly over the surface of the rod. We want to set up an integral to find the electric field at location < 0, y, 0> due to the rod. Following the procedure discussed in the textbook, we have cut up the rod into small segments, each of which can be considered as a point charge. We have selected a typical piece, shown in red on the diagram. * Your answer is incorrect. For a disk of radius R = 22 cm and Q = 4x 106 C, calculate the electric field 2 cm from the center of the disk using all three formulas below, and using the accurate value 0 = 8.85 x 10-12 C²/(N-m²). (a) most accurate approximation: E = 135169007.8 (b) less accurate approximation: E = 135113519.5 N/C 148624871.4 N/C (c) least accurate approximation: E = QIA 200 QIA 200 [1- QIA 20 - 1/2 (R² +2²) ¹¹/² Ē
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