Taylor series the taylor series generated by f(x) at x=a is .. f(a) F(a) f(a)+ (x - a) + (x-( a)²+...... (x-a)n 1! 2! fn(a) n! Example/find the taylor series for f(x)=cos x at x=2π. Soltion// f(x)cos x. ƒ(2π) = 1 f(x) = -sinx. ƒ(2π) = 0 F(x) = - COS X. F(2π) = =-1 The taylor series is 1 1+0- (x- -2)²+..... 2! Example/find the taylor series for f(x)= ½- at x=2. Soltion// 1 f(x) == ½ ½ ƒ(2) = 1/1 f(x) = 11. F(2) 2 1 7(x) = 23. 7(2) = 1/13 - 11 = 8 4 = 44 The taylor series is 1 1 (x-2)+ 2 4 * 1! 1 4 * 2! (x − 2)²+..... -

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
I hope that you will clarify this topic again and solve the examples in detail, and I am confident that I will give you an upvote. Thank you.....
Taylor series
the taylor series generated by f(x) at x=a is ..
f(a)
F(a)
f(a)+
(x
-
a) +
(x-( a)²+...... (x-a)n
1!
2!
fn(a)
n!
Example/find the taylor series for f(x)=cos x at x=2π.
Soltion//
f(x)cos x. ƒ(2π) = 1
f(x) = -sinx.
ƒ(2π) = 0
F(x)
= - COS X.
F(2π) =
=-1
The taylor series is
1
1+0-
(x- -2)²+.....
2!
Example/find the taylor series for f(x)= ½- at x=2.
Soltion//
1
f(x) == ½ ½ ƒ(2) = 1/1
f(x) = 11. F(2)
2 1
7(x) = 23. 7(2) = 1/13 - 11
=
8 4
=
44
The taylor series is
1
1
(x-2)+
2
4 * 1!
1
4 * 2!
(x − 2)²+.....
-
Transcribed Image Text:Taylor series the taylor series generated by f(x) at x=a is .. f(a) F(a) f(a)+ (x - a) + (x-( a)²+...... (x-a)n 1! 2! fn(a) n! Example/find the taylor series for f(x)=cos x at x=2π. Soltion// f(x)cos x. ƒ(2π) = 1 f(x) = -sinx. ƒ(2π) = 0 F(x) = - COS X. F(2π) = =-1 The taylor series is 1 1+0- (x- -2)²+..... 2! Example/find the taylor series for f(x)= ½- at x=2. Soltion// 1 f(x) == ½ ½ ƒ(2) = 1/1 f(x) = 11. F(2) 2 1 7(x) = 23. 7(2) = 1/13 - 11 = 8 4 = 44 The taylor series is 1 1 (x-2)+ 2 4 * 1! 1 4 * 2! (x − 2)²+..... -
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