Tax increase - A city councilor asks your advice on how many householders should be polled in order to gauge the support for a tax increase to build more schools. 1. The councilor wants to assess the support with a margin of error no more than 0.047 with 95% confidence. What sample size would you recommend if the councilor has no information about the proportion of householders who would support a tax increase? Round your z* value to three decimal places when calculating your answer. Give your answer as an integer. n = 2. Suppose you conduct the survey and construct a 99% confidence interval for the true proportion of householders who are in favor of the tax increase to be (0.483, 0.614). Determine whether the statements below are correct or incorrect interpretations of the confidence interval. A. Correct B. Incorrect 1. If we collected another random sample of the same size, there is a 99% chance the new sample proportion will be between 0.483 and 0.614. 2. We can be 99% confident that the true proportion of householders who are in favor of the tax increase is contained in the interval (0.483, 0.614). ? v 3. There is a 99% chance that 54.85% of householders are in favor of the tax increase. v 4. We can expect that 99% of the intervals we construct using this method will contain the true proportion of householders who are in favor of the tax increase. v 5. 99% of the time, the true proportion of householders that are in favor of the tax increase between 0.483 and 0.614.
Tax increase - A city councilor asks your advice on how many householders should be polled in order to gauge the support for a tax increase to build more schools. 1. The councilor wants to assess the support with a margin of error no more than 0.047 with 95% confidence. What sample size would you recommend if the councilor has no information about the proportion of householders who would support a tax increase? Round your z* value to three decimal places when calculating your answer. Give your answer as an integer. n = 2. Suppose you conduct the survey and construct a 99% confidence interval for the true proportion of householders who are in favor of the tax increase to be (0.483, 0.614). Determine whether the statements below are correct or incorrect interpretations of the confidence interval. A. Correct B. Incorrect 1. If we collected another random sample of the same size, there is a 99% chance the new sample proportion will be between 0.483 and 0.614. 2. We can be 99% confident that the true proportion of householders who are in favor of the tax increase is contained in the interval (0.483, 0.614). ? v 3. There is a 99% chance that 54.85% of householders are in favor of the tax increase. v 4. We can expect that 99% of the intervals we construct using this method will contain the true proportion of householders who are in favor of the tax increase. v 5. 99% of the time, the true proportion of householders that are in favor of the tax increase between 0.483 and 0.614.
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I need help with 1 and 2 plz.
![### Tax Increase Polling Analysis
A city councilor seeks advice on how many householders should be polled to gauge support for a tax increase to build more schools.
#### 1. Determining Sample Size
The councilor wishes to assess support with a margin of error no more than 0.047 with 95% confidence. What sample size is recommended if the councilor has no information about the proportion of householders who would support a tax increase?
Formula to use:
\[ n = \left( \frac{z^*}{2(\text{Margin of Error})} \right)^2 \]
- Round your \( z^* \) value to three decimal places.
- Give your answer as an integer.
\[ n = \_\_\_\_\_\_ \]
#### 2. Confidence Interval Interpretation
Suppose you conduct the survey and construct a 99% confidence interval for the true proportion of householders who are in favor of the tax increase to be (0.483, 0.614). Determine whether the following statements are correct or incorrect interpretations of the confidence interval.
- **Correct**
- **Incorrect**
1. **If we collected another random sample of the same size, there is a 99% chance the new sample proportion will be between 0.483 and 0.614.**
- ___
2. **We can be 99% confident that the true proportion of householders who are in favor of the tax increase is contained in the interval (0.483, 0.614).**
- ___
3. **There is a 99% chance that 54.85% of householders are in favor of the tax increase.**
- ___
4. **We can expect that 99% of the intervals we construct using this method will contain the true proportion of householders who are in favor of the tax increase.**
- ___
5. **99% of the time, the true proportion of householders that are in favor of the tax increase is between 0.483 and 0.614.**
- ___
This exercise will help understand the construction and interpretation of confidence intervals in statistical analysis, particularly in survey-based research.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9896e9f0-21a4-41f5-9cfe-a9d2b9678883%2F66684562-3403-48bc-960c-592a623da752%2Fj2dfbd_processed.png&w=3840&q=75)
Transcribed Image Text:### Tax Increase Polling Analysis
A city councilor seeks advice on how many householders should be polled to gauge support for a tax increase to build more schools.
#### 1. Determining Sample Size
The councilor wishes to assess support with a margin of error no more than 0.047 with 95% confidence. What sample size is recommended if the councilor has no information about the proportion of householders who would support a tax increase?
Formula to use:
\[ n = \left( \frac{z^*}{2(\text{Margin of Error})} \right)^2 \]
- Round your \( z^* \) value to three decimal places.
- Give your answer as an integer.
\[ n = \_\_\_\_\_\_ \]
#### 2. Confidence Interval Interpretation
Suppose you conduct the survey and construct a 99% confidence interval for the true proportion of householders who are in favor of the tax increase to be (0.483, 0.614). Determine whether the following statements are correct or incorrect interpretations of the confidence interval.
- **Correct**
- **Incorrect**
1. **If we collected another random sample of the same size, there is a 99% chance the new sample proportion will be between 0.483 and 0.614.**
- ___
2. **We can be 99% confident that the true proportion of householders who are in favor of the tax increase is contained in the interval (0.483, 0.614).**
- ___
3. **There is a 99% chance that 54.85% of householders are in favor of the tax increase.**
- ___
4. **We can expect that 99% of the intervals we construct using this method will contain the true proportion of householders who are in favor of the tax increase.**
- ___
5. **99% of the time, the true proportion of householders that are in favor of the tax increase is between 0.483 and 0.614.**
- ___
This exercise will help understand the construction and interpretation of confidence intervals in statistical analysis, particularly in survey-based research.
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