Task: Assume that at time 0 a sum L is lent for a series of n yearly payments. The rth payment, of amount x, is due at the end of the rth year. Let the effective annual interest rate for the rth year be i. Give an identity which expresses L in terms of the x, and i. Answer: The identity is [ Select ] [ Select ] L= x_1 (1+i_1)^(-1) + x_2 (1+i_1)^(-1) (1+i_2)^(-2) + ... + x_n (1+i_1)^(-1) (1+i_2)^(-2) ... (1+i_n)^(-n) L= x_1 (1+i_1) + x_2 (1+i_1) (1+i_2) + ... + x_n (1+i_1) (1+i_2) ... (1+i_n) L= x_1 (1+i_1)^(-1) + x_2 (1+i_1)^(-1) (1+i_2)^(-1) + .. + x_n (1+i_1)^(-1) (1+i_2)^(-1) ... (1+i_n)^(-1) Question 3 L=x_1 (1+i_1) + x_2 (1+i_1) (1+i_2)^2 + ... + x_n (1+i_1) (1+i_2)^2 ... (1+i_n)^n
Task: Assume that at time 0 a sum L is lent for a series of n yearly payments. The rth payment, of amount x, is due at the end of the rth year. Let the effective annual interest rate for the rth year be i. Give an identity which expresses L in terms of the x, and i. Answer: The identity is [ Select ] [ Select ] L= x_1 (1+i_1)^(-1) + x_2 (1+i_1)^(-1) (1+i_2)^(-2) + ... + x_n (1+i_1)^(-1) (1+i_2)^(-2) ... (1+i_n)^(-n) L= x_1 (1+i_1) + x_2 (1+i_1) (1+i_2) + ... + x_n (1+i_1) (1+i_2) ... (1+i_n) L= x_1 (1+i_1)^(-1) + x_2 (1+i_1)^(-1) (1+i_2)^(-1) + .. + x_n (1+i_1)^(-1) (1+i_2)^(-1) ... (1+i_n)^(-1) Question 3 L=x_1 (1+i_1) + x_2 (1+i_1) (1+i_2)^2 + ... + x_n (1+i_1) (1+i_2)^2 ... (1+i_n)^n
Essentials Of Investments
11th Edition
ISBN:9781260013924
Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.
Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.
Chapter1: Investments: Background And Issues
Section: Chapter Questions
Problem 1PS
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![Task: Assume that at time 0 a sum L is lent for a series of n yearly payments. The rth payment, of amount x, is due
at the end of the rth year. Let the effective annual interest rate for the rth year be i,.
Give an identity which expresses L in terms of the x, and i,.
Answer: The identity is
[ Select ]
[ Select ]
L = x_1 (1+i_1)^(-1) + x_2 (1+i_1)^(-1) (1+i_2)^(-2) + .. + x_n (1+i_1)^(-1) (1+i_2)^(-2) ... (1+i_n)^(-n)
L = x_1 (1+i_1) + x_2 (1+i_1) (1+i_2) + ... + x_n (1+i_1) (1+i_2) ... (1+i_n)
L = x_1 (1+i_1)^(-1) + x_2 (1+i_1)^(-1) (1+i_2)^(-1) + .. + x_n (1+i_1)^(-1) (1+i_2)^(-1) ... (1+i_n)^(-1)
Question 3
L = x_1 (1+i_1) + x_2 (1+i_1) (1+i_2)^2 + ... + x_n (1+i_1) (1+i_2)^2 ... (1+i_n)^n](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2731f2f8-549b-4c95-b876-fd63e857b145%2F9b2edd2d-3461-40bb-8d6b-0db4ee9cda81%2Fexd54bq_processed.png&w=3840&q=75)
Transcribed Image Text:Task: Assume that at time 0 a sum L is lent for a series of n yearly payments. The rth payment, of amount x, is due
at the end of the rth year. Let the effective annual interest rate for the rth year be i,.
Give an identity which expresses L in terms of the x, and i,.
Answer: The identity is
[ Select ]
[ Select ]
L = x_1 (1+i_1)^(-1) + x_2 (1+i_1)^(-1) (1+i_2)^(-2) + .. + x_n (1+i_1)^(-1) (1+i_2)^(-2) ... (1+i_n)^(-n)
L = x_1 (1+i_1) + x_2 (1+i_1) (1+i_2) + ... + x_n (1+i_1) (1+i_2) ... (1+i_n)
L = x_1 (1+i_1)^(-1) + x_2 (1+i_1)^(-1) (1+i_2)^(-1) + .. + x_n (1+i_1)^(-1) (1+i_2)^(-1) ... (1+i_n)^(-1)
Question 3
L = x_1 (1+i_1) + x_2 (1+i_1) (1+i_2)^2 + ... + x_n (1+i_1) (1+i_2)^2 ... (1+i_n)^n
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