Task 2: Grading A professor will give the number of students and their grades. You need to calculate the number of students whose grade is less than the average. (base) sebasjr@sebasjr-ubuntu:~$ ./a.out how many students do you have?5 Input the grades 1 2 3 4 10 The number of students who fail is 3 (base) sebasjr@sebasjr-ubuntu:~$ ./a.out how many students do you have?8 Input the grades 1 6 3 8 1 5 2 4 The number of students who fail is 4

In this exercise, you modify the Grade Calculator application from this chapter’s Apply lesson. Use Windows to make a copy of the Grade Solution folder. Rename the copy Grade Solution-Intermediate. Open the Grade Solution.sln file contained in the Grade Solution-Intermediate folder. Open the CourseGrade.vb file. The DetermineGrade method should accept an integer that represents the total number of points that can be earned in the course. (Currently, the total number of points is 200: 100 points per test.) For an A grade, the student must earn at least 90% of the total points. For a B, C, and D grade, the student must earn at least 80%, 70%, and 60%, respectively. If the student earns less than 60% of the total points, the grade is F. Make the appropriate modifications to the DetermineGrade method and then save the solution. Unlock the controls on the form. Add a label control and a text box to the form. Change the label control’s Text property to “&Maximum points:” (without the quotation marks). Change the text box’s name to txtMax. Lock the controls and then reset the tab order. Open the form’s Code Editor window. The txtMax control should accept only numbers and the Backspace key. Code the appropriate procedure. The grade should be cleared when the user makes a change to the contents of the txtMax control. Code the appropriate procedure. Modify the frmMain_Load procedure so that each list box displays numbers from 0 through 200. Locate the btnDisplay_Click procedure. If the txtMax control does not contain a value, display an appropriate message. The maximum number allowed in the txtMax control should be 400; if the control contains a number that is more than 400, display an appropriate message. The statement that calculates the grade should pass the maximum number of points to the studentGrade object’s DetermineGrade method. Make the necessary modifications to the procedure. Save the solution and then start and test the application.

For each of the following exercises, you may choose to write a console-based or GUI application, or both. Write a program named TestScoreList that accepts eight int values representing student test scores. Display each of the values along with a message that indicates how far it is from the average.

When you borrow money to buy a house, a car, or for some other purpose, you repay the loan by making periodic payments over a certain period of time. Of course, the lending company will charge interest on the loan. Every periodic payment consists of the interest on the loan and the payment toward the principal amount. To be specific, suppose that you borrow $1,000 at an interest rate of 7.2% per year and the payments are monthly. Suppose that your monthly payment is $25. Now, the interest is 7.2% per year and the payments are monthly, so the interest rate per month is 7.2/12 = 0.6%. The first months interest on $1,000 is 1000 0.006 = 6. Because the payment is $25 and the interest for the first month is $6, the payment toward the principal amount is 25 6 = 19. This means after making the first payment, the loan amount is 1,000 19 = 981. For the second payment, the interest is calculated on $981. So the interest for the second month is 981 0.006 = 5.886, that is, approximately $5.89. This implies that the payment toward the principal is 25 5.89 = 19.11 and the remaining balance after the second payment is 981 19.11 = 961.89. This process is repeated until the loan is paid. Write a program that accepts as input the loan amount, the interest rate per year, and the monthly payment. (Enter the interest rate as a percentage. For example, if the interest rate is 7.2% per year, then enter 7.2.) The program then outputs the number of months it would take to repay the loan. (Note that if the monthly payment is less than the first months interest, then after each payment, the loan amount will increase. In this case, the program must warn the borrower that the monthly payment is too low, and with this monthly payment, the loan amount could not be repaid.)

What is the result of the following expression: 3 * 5 \ 2 + 30 / 5? 7.5 13 13.5 None of the above.

Rewrite the Loop clause from Question 1 using the Until keyword.