Tarzan grabs a vine hanging vertically from a tall tree when he is running at 9.0 m/s. (a) How high can he swing upward?
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- If a marble is launched upward with an initial velocity of 15 m/s from a slingshot. Using conservation of energy, how high in meters will the marble go? Round to one decimal.The horizontal and vertical velocity components of a 2.0 Kg projectile are Vh = 30 m/s and Vv = 40 m/s, respectively. Find the work performed to enable this projectile to launch.Tarzan grabs a vine hanging vertically from a tall tree when he is running at 9.0m/s.. (a) How high can he swing upward? (b) Does the length of the vine affect this height?
- Disregarding friction, a roller coaster with a vertical drop of 46 m will achieve a speed of about 30 m/s. If the height of the drop is doubled, how much the speed is going to be?What formula would I need to use to solve this problem: The rope of a swing is 2.90 m long. Calculate the angle from the vertical at which a 84.0 kg man must begin to swing in order to have the same KE at the bottom as a 1440 kg car moving at 1.41 m/s (3.15 mph). The decrease in gravitational PE is converted into KE as the man falls. This decrease in gravitational PE depends on the change in height.Tarzan grabs a vine of length L=8.9 m and attempts to swing across the crocodile infested river. The vine breaks just as Tarzan is at lowest point of his swing, a horizontal distance D=60 m and H= 4.5 m above the riverbank. You barely mix it across, landing on the edge of the riverbank. The tension in the vine when it broke was a 1000 N. Find Tarzan's mass.
- A gymnast is swinging on a high bar. The distance between his waist and the bar is 1.28 m, as the drawing shows. At the top of the swing his speed is momentarily zero. Ignoring friction and treating the gymnast as if all of his mass is located at his waist, find his speed at the bottom of the swing.(a) A stuntman with a mass of 81.5 kg swings across a pool of water from a rope that is 11.0 m. At the bottom of the swing the stuntman's speed is 7.90 m/s. The rope's breaking strength is 1,000 N. Will the stuntman make it across the pool without falling in? O Yes O No (b) What If? What is the maximum speed (in m/s) that the stuntman can have at the bottom of the swing on this vine to safely swing across the river? m/sA proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 9.80 × 101¹1 m/s² in a machine. If the proton has an initial speed of 5.40 × 104 m/s and travels 3.80 cm, what then is (a) its speed and (b) the increase in its kinetic energy?
- Consider a 0.5 kg mass at the top of a 1.5 m high (vertical) incline. if it is allowed to slide down with negligible friction, what will be its speed (in m/s) at the bottom?I need help with this homework problem.A 1700 kg car starts up a 130 m long hill at a speed of 20.0 m/s. If the propulsive force (up the slope) is 15.0 kN, while the resistive force (due to friction/AR) is 8.79 kN, then determine the car's kinetic energy when it reaches a vertical height of 48.1 m at the top of the hill. can you please write it down instead so I can follow it better