tan(x) – 4 sec(x) f'(x) = cos(x) + 4 sin(x) If f(x) = f'(-3) = -.43 then: I q X

Q: If f(x) = 4x(sin x + cos a), find f'(x) = COS f'(2) =

A:

Q: Given f''(x) = - 36 sin(6x) and f'(0) = 6 and f(0) = 0. 70 Find f)

A: Given that      f"(x)= -36sin(6x) , f'(0)=6 and f(0)=0 .

Q: If f(x) = cos a- 5 tanx, then %3D f'(x) = %3D f'(5) =

A:

Q: Let f'(x) = f'( 5 ) = f(x) = 3 sin x + 12 cos x

A:

Q: Let h(x) =tan(3x + 5). Then h' (4) is 3 sec² (17) 2 and h''(4) is

A:

Q: If f(x) = 7 tan-(2 sin(4)), f'(2) =|

A:

Q: If f(x) f'(x) = f'(4) = = 4 sin x 3 + cos x " then

A:

Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

Q: If f(x) = 2 tan-'(8 sin(4x)), f'(x) =

A:

Q: If f(x) f'(x) = COS x 3 tan x, then - f' (5) =

A: Derivative of cosx is -sinx.

Q: Find f''(x) if f(x)=ex cos(x)+x3

A: Find f''(x) if f(x)=ex cos(x)+x3

Q: If f(x) = 3 tan-'(3 sin(3x)), f'(æ) =

A: The given function f(x)=3tan-13 sin(3x)

Q: If f(x) = f'(x) = f'(1) = 5 sin x 3+ cos x then

A:

Q: Let f(x) = 7x sin(x) cos(x). Evaluate f'(x) at x = ³7. ƒ'( ³ ) =

A: I have appended the formula used in the solution part of the question

Q: Given f''(x) = - 25 sin(5x) and f'(0) = 2 and f(0) = -6. Find f() =

A: In this question, we want to compute the value of f at the given point.

Q: f(x) = 7 sinx+ 5 cos x

A: