Take period, T=2ms, tstep as T/100. 1) Take t=tstep:tstep:T ; and find ACF for x(1)=2* sin(2 * pi * 1 /T) 2) Repeat (1) for t=tstep:tstep:3*T; Explain why ACF magnitude decreases for successive periods? What happens if we set t(end)=5T, 10T etc.? Comment on your lab report.

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A: Given:   We have to show that  if an = 5n3 - 14n2 + 7n - 3, then an = Θ(n3)

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