Take a look at the code in the editor it reads a float value, puts itinto a variable named x, and prints the value of a variable namedy. Your taskis to complete the code in order to evaluate the following expression: < > main.py 1 * = # hardcode your test data here 2 x- float(x) 3 urite your code here 4 print("y =", y) 3x² - 2x² + 3x -1 Theresult should be assigned toy. Remember that classical algebraic notation likes to omit the multiplication operator - you need to use it explicitly. Note howwe change data type to make sure that xis of type float + II
Take a look at the code in the editor it reads a float value, puts itinto a variable named x, and prints the value of a variable namedy. Your taskis to complete the code in order to evaluate the following expression: < > main.py 1 * = # hardcode your test data here 2 x- float(x) 3 urite your code here 4 print("y =", y) 3x² - 2x² + 3x -1 Theresult should be assigned toy. Remember that classical algebraic notation likes to omit the multiplication operator - you need to use it explicitly. Note howwe change data type to make sure that xis of type float + II
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:Take a look at the code in the editor it reads a float value, puts
it into a variable named x, and prints the value of a variable
named y. Your task is to complete the code in order to evaluate
the following expression:
< > main.py
1 * = # hardcode your test data here
2 x - float(x)
3 * write your code here
4 print("y =", y)
3x² - 2x² + 3x - 1
The result should be assigned to y.
Remember that classical algebraic notation likes to omit the
multiplication operator - you need to use it explicity.Note
how we change data type to make sure that x is of type float.
+
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