Tables: employees (id(pk), name, job_code(fk)) jobs (code(pk), title, salary) mysql> SELECT * FROM employees; . | id | name | 1 | Captain Hook | 2 | Tiger Lily | 3 | Pocahontas | 4 | Meeko 4 rows in set (0.00 sec) mysql> select from jobs; code title | salary | 1 author | 100.50 2 | editor | 200.00 3 manager | 150.00 3 rows in set (0.00 sec) How many rows will the following commands return? | job_code | foreign key references jobs (code) 21 21 1 | (a) SELECT name, salary FROM employees LEFT JOIN jobs ON job_code - code; (b) SELECT name, salary FROM employees RIGHT JOIN jobs ON job_code = code; [Select] [Select]

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Refer to the sample tables and data below.
Tables:
employees (id(pk), name, job_code(fk))
jobs (code (pk), title, salary)
mysql> SELECT * FROM employees;
| id | name
+--
|
1 | Captain Hook
2
Tiger Lily
3 | Pocahontas
4 | Meeko
4 rows in set (0.00 sec)
mysql> select * from jobs;
| code
title | salary |
+-
I
author | 100.50
200.00
|
editor
3 manager 150.00 |
|
1
2
I job_code
3 rows in set (0.00 sec)
2
1 |
foreign key references jobs (code)
How many rows will the following commands return?
(a) SELECT name, salary FROM employees LEFT JOIN jobs ON job_code
= code;
(b) SELECT name, salary FROM employees RIGHT JOIN jobs ON job_code = code;
[Select]
[Select]
Transcribed Image Text:Refer to the sample tables and data below. Tables: employees (id(pk), name, job_code(fk)) jobs (code (pk), title, salary) mysql> SELECT * FROM employees; | id | name +-- | 1 | Captain Hook 2 Tiger Lily 3 | Pocahontas 4 | Meeko 4 rows in set (0.00 sec) mysql> select * from jobs; | code title | salary | +- I author | 100.50 200.00 | editor 3 manager 150.00 | | 1 2 I job_code 3 rows in set (0.00 sec) 2 1 | foreign key references jobs (code) How many rows will the following commands return? (a) SELECT name, salary FROM employees LEFT JOIN jobs ON job_code = code; (b) SELECT name, salary FROM employees RIGHT JOIN jobs ON job_code = code; [Select] [Select]
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