7.7 A mini-grid is to be implemented for the community of Ababju. The com-munity has 500 households. Each household is expected to consume 600 Wh perday. Assume the power consumption is constant throughout the day. Let the dailyirradiance of Ababju be27 (t – 6)G(t)700 sin24where t is in hours (valid between sunrise t = 6 and sunset t =many of the modules described in Table 7.3 are needed to power Ababju. Assumethat the mini-grid contains sufficient and lossless energy storage so that the excessenergy produced during the day can be used to power the load in the evening.18). Determine how Table 7.3 Electrical characteristics of PV module A and module BCharacteristic at STCModule AModule BMaximum power350 W20 WOptimum operating voltage (V*)Optimum operating current (I*)38.54 V18 V9.08 A1.11 AOpen-circuit voltage (Voc)47.43 V22.5 VShort-circuit current (Isc)9.49 A1.23 AShort-circuit current temp. coeff. (œ¡)0.040 %/K0.045%/K-0.34 %/KOpen-circuit voltage temp. coeff. (æ,)Мах. power temp. cоeff. (a p)-0.29 %/K-0.38 %/K-0.47 %/KNOCT45°C47°CNumber of cells72 (series)36 (series)

Given Number of houses = 500 Energy consumption per house = 600 Wh Irradiance Gt =700sin2πt-624t =…

Table 7.3 Electrical characteristics of PV module A and module B Characteristic at STC Module A Module B Maximum power 350 W 20 W Optimum operating voltage (V*) Optimum operating current (I*) Open-circuit voltage (Voc) 38.54 V 18 V 9.08 A 1.11 A 47.43 V 22.5 V Short-circuit current (Isc) 9.49 A 1.23 A Short-circuit current temp. coeff. (a¡) 0.040 %/K 0.045%/K Open-circuit voltage temp. coeff. (æv) -0.29 %/K -0.34 %/K Max. power temp. coeff. (ap) -0.38 %/K -0.47 %/K NOCT 45°C 47°C Number of cells 72 (series) 36 (series)

Table 7.3 Electrical characteristics of PV module A and module B Characteristic at STC Module A Module B Maximum power 350 W 20 W Optimum operating voltage (V) Optimum operating current (I) Open-circuit voltage (Voc) 38.54 V 18 V 9.08 A 1.11 A 47.43 V 22.5 V Short-circuit current (Isc) 9.49 A 1.23 A Short-circuit current temp. coeff. (a¡) 0.040 %/K 0.045%/K Open-circuit voltage temp. coeff. (æv) -0.29 %/K -0.34 %/K Max. power temp. coeff. (ap) -0.38 %/K -0.47 %/K NOCT 45°C 47°C Number of cells 72 (series) 36 (series)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

If 3-phase transfomer configuration in figure in has the givens as listed below: E-line on high side = 480V, turns ration = 2:1/coil, resistance per load =10, efficienscy = 100%. E/coil on the high side is _____, E/coil on the low side is___, E-phase on the low side is____, E/resitor of the load is____,(a-480v, b-240v, c-120 d-69.28v) I/resitor on the load is____, I-line on the low side is___, I-phase on the low side is____, I/coil on the low side is____(a-2A b-4A c-6.93 d-12A), I-phase on the high side is____, I-line on the high side is____(a-1A b-1.73A c-2A d-4A), Va/phase of the load is____, 3-phase Va on the high side is____(a-120VA b-360VA c-480VA d-1440VA).
Give the suitable solution for the following The non-conventional sources of energy are........ The diesel power station cannot be located at any place (T or F) The d.c resistance of various types of conductors at specified temperature (T) is found by...... The self-GMD of a conductor depends upon the ...... ...... and ..................of the conductor The voltage drop is increased if the length of transmission line is increased (T or F) The skin effect depends upon the.............. ........ and ********* , and..... …........
How does distributed generation contribute to grid resilience, and what are some common sources of distributed energy resources (DERs)?
A series resistance – capacitance (R – C) circuit is connected to 230 – volt, 50 cycle AC source. The current through the resistor is 45.45 A and the power taken by the circuit is 5,000 watts. Compute the following: 1.) Power factor angle 2.) Circuit impedance 3.) Ohmic value of the resistor
Explain the concept of FACTS (Flexible Alternating Current Transmission Systems) devices. How do they enhance the control and stability of power systems? Provide examples of FACTS devices and their applications.
A low voltage distribution transformer feeds two different loads with a three-phase line. The nominal voltage of the line is 400 Volt. The total length of the feeder is 500 m. The distance from the transformer to these loads is 140 m and 340 m, respectively. Their consumption is 11 kVA with a 0.8 lagging power factor and 10 kW with a 0.8 lagging power factor, respectively. The feeder's cross-section is 15 mm2 and the feeder's conductivity is 56 m/ohm.mm2. Find the following information. The distance from the transformer to the maximum voltage drop point is m The maximum voltage drop is Volt The power loss between the transformer and 11 kVA load is Watt.
Power systems quality
design 800v to 14.5v isolated bi-directional dcdc conveter a. choose the converter type with reason b. design each components with safety margin 30% (equations) c. calculate the efficiency (equations)
The zener regulator 5.6 V DC is interfaced with 6.4 V DC relay. How many voltages should be provided by the DC power supply as shown in given Figure?
Give the analogous quantities for electrical current in pneumatic, hydraulic and thermal systems. b. Give example for isomorphic electric, pneumatic, hydraulic and thermal systems.
QUESTION THREE A 3-phase full converter is fed from 3-phase, 230 V, 50 Hz supply having per-phase source inductance of 4 mH. The load current is 10 A ripple free. (a) Calculate the voltage drop in de output voltage due to source inductance. (b) If de output voltage is 210 V, calculate the firing angle and the overlap period.
(5) Primary AC Source Transformer Secondary AC/DC Full-wave Rectifier Capaictor in Non- linear Load Figure 6 Analyse different methods of harmonics mitigation to eliminate the harmonic, which you have identify in above power system circuit. You can use harmonic filters, K or equivalent transformers or oversized neutral method depending upon the harmonic sources.