Very importante: perfom in excel (show pictures) (and show the formulas)the exercise is in the images as well--------------------The data shown in Table 6E.2 are x and R values for 24 samples of size n = 5 taken from a process producing bearings. The measurements are made on the inside diameter of the bearing, with only the last threedecimals recorded (i.e., 34.5 should be 0.50345).(a) Set up x and R charts on this process. Does the process seem to be in statistical control? If necessary, revise the trial control limits(b) If specifications on this diameter are 0.5030 ± 0.0010, find the percentage of nonconforming bearings produced by this process. Assume that diameter is normally distributed - TABLE 6E.2Bearing Diameter DataSampleNumber iSampleNumberR134.531335.48.234.241434.06331.641537.15431.541634.97535.051733.5434.16.1831.73732.641934.08.833.832035.14.9.34.872133.721033.682232.811131.932333.531238.692434.22inside diameter of the bearing, with only the last threedecimals recorded (i.e., 34.5 should be 0.50345).(a) Set up ī and R charts on this process. Does theprocess seem to be in statistical control? If nec-essary, revise the trial control limits.(b) If specifications on this diameter are 0.5030 ±0.0010, find the percentage of nonconformingbearings produced by this process. Assume thatdiameter is normally distributed. 6.7. The data shown in Table 6E.2 are ī and R values for24 samples of size n=5 taken from a process produc-ing bearings. The measurements are made on the

Answered: TABLE 6E.2 Bearing Diameter Data Sample…

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Very importante: perfom in excel (show pictures) (and show the formulas)

the exercise is in the images as well

--------------------

The data shown in Table 6E.2 are x and R values for 24 samples of size n = 5 taken from a process producing bearings. The measurements are made on the inside diameter of the bearing, with only the last three
decimals recorded (i.e., 34.5 should be 0.50345).

(a) Set up x and R charts on this process. Does the process seem to be in statistical control? If necessary, revise the trial control limits

(b) If specifications on this diameter are 0.5030 ± 0.0010, find the percentage of nonconforming bearings produced by this process. Assume that diameter is normally distributed

- TABLE 6E.2
Bearing Diameter Data
Sample
Number i
Sample
Number
R
1
34.5
3
13
35.4
8.
2
34.2
4
14
34.0
6
3
31.6
4
15
37.1
5
4
31.5
4
16
34.9
7
5
35.0
5
17
33.5
4
34.1
6.
18
31.7
3
7
32.6
4
19
34.0
8.
8
33.8
3
20
35.1
4.
9.
34.8
7
21
33.7
2
10
33.6
8
22
32.8
1
11
31.9
3
23
33.5
3
12
38.6
9
24
34.2
2
inside diameter of the bearing, with only the last three
decimals recorded (i.e., 34.5 should be 0.50345).
(a) Set up ī and R charts on this process. Does the
process seem to be in statistical control? If nec-
essary, revise the trial control limits.
(b) If specifications on this diameter are 0.5030 ±
0.0010, find the percentage of nonconforming
bearings produced by this process. Assume that
diameter is normally distributed.

6.7. The data shown in Table 6E.2 are ī and R values for
24 samples of size n=5 taken from a process produc-
ing bearings. The measurements are made on the

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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