Table 2.1. Unknown Mixture Identification Code: Filter paper weight 0.906g Glassware and Component Mass Evaporating Dish (g). 42.7739 Evaporating Dish + Sample (g) 43.3243 Sample (g) 0.551 Beaker A (g) 67.9943 Beaker A + NaCI (g) 68.416g NaCl (g) 0.4929 Evaporating Dish (g) 42.773g Evaporating Dish + Sio, (g) 43.002g SiO, (g) 0.229 9 Evaporating Dish + Filter Paper (g) 43.6799 Evaporating Dish + Filter Paper + CaCO, (g) 43.8749 CaCO, (g) 0.195g Table 2.2. Unknown Mixture Identification Code: Glassware and Component Mass Mass Sample (g) Mass NaCl (g) % NaCl in Mixture Mass SiO, (g) % Sio, in Mixture Mass CaCO, (g) % CACO, in Mixture NaCl, SiO, CaCo, recovered (g) Total % Recovery
Table 2.1. Unknown Mixture Identification Code: Filter paper weight 0.906g Glassware and Component Mass Evaporating Dish (g). 42.7739 Evaporating Dish + Sample (g) 43.3243 Sample (g) 0.551 Beaker A (g) 67.9943 Beaker A + NaCI (g) 68.416g NaCl (g) 0.4929 Evaporating Dish (g) 42.773g Evaporating Dish + Sio, (g) 43.002g SiO, (g) 0.229 9 Evaporating Dish + Filter Paper (g) 43.6799 Evaporating Dish + Filter Paper + CaCO, (g) 43.8749 CaCO, (g) 0.195g Table 2.2. Unknown Mixture Identification Code: Glassware and Component Mass Mass Sample (g) Mass NaCl (g) % NaCl in Mixture Mass SiO, (g) % Sio, in Mixture Mass CaCO, (g) % CACO, in Mixture NaCl, SiO, CaCo, recovered (g) Total % Recovery
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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