TABLE 15.5 Acid lonization Constants (Ka) for Some Monoprotic Weak Acids at 25 °C Acid Formula Structural Formula lonization Reaction K. HCIO2(aq) + H20(0) -2 Chlorous acid HCI02 1.1 x 10 H3o(a) CIO2 (aq) HNO2(aq) +H200)- Nitrous acid HNO2 4.6 x 10 H30(aq) NO2(aq) HF(aq) H200)- Hydrofluoric acid HF H-F 3.5 x 10 H3o (a) F(aq) 0 нсног(aq) H2 0(1) + Formic acid нсног 1.8 x 104 H30(a) CHO2 (aq) HC7H502(aq) H200) Benzoic acid HC7H502 CH 6.5 x 10 H30(aq) C7H502 (aq) C-C 0 C2302(aq) H20U) Acetic acid HC2H302 1.8 x 10 H-0-0-CH3 H30() C2H302 (aq)
TABLE 15.5 Acid lonization Constants (Ka) for Some Monoprotic Weak Acids at 25 °C Acid Formula Structural Formula lonization Reaction K. HCIO2(aq) + H20(0) -2 Chlorous acid HCI02 1.1 x 10 H3o(a) CIO2 (aq) HNO2(aq) +H200)- Nitrous acid HNO2 4.6 x 10 H30(aq) NO2(aq) HF(aq) H200)- Hydrofluoric acid HF H-F 3.5 x 10 H3o (a) F(aq) 0 нсног(aq) H2 0(1) + Formic acid нсног 1.8 x 104 H30(a) CHO2 (aq) HC7H502(aq) H200) Benzoic acid HC7H502 CH 6.5 x 10 H30(aq) C7H502 (aq) C-C 0 C2302(aq) H20U) Acetic acid HC2H302 1.8 x 10 H-0-0-CH3 H30() C2H302 (aq)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
(7): Calculate the pH and percent deprotonation of 0.10 M acetic acid CH3COOH (aq)
(use Table 15.5 to find the Ka of this weak acid)

Transcribed Image Text:TABLE 15.5
Acid lonization Constants (Ka) for Some Monoprotic Weak Acids at 25 °C
Acid
Formula
Structural Formula
lonization Reaction
K.
HCIO2(aq) + H20(0)
-2
Chlorous acid
HCI02
1.1 x 10
H3o(a) CIO2 (aq)
HNO2(aq) +H200)-
Nitrous acid
HNO2
4.6 x 10
H30(aq) NO2(aq)
HF(aq) H200)-
Hydrofluoric acid
HF
H-F
3.5 x 10
H3o (a) F(aq)
0
нсног(aq)
H2
0(1)
+
Formic acid
нсног
1.8 x 104
H30(a) CHO2 (aq)
HC7H502(aq) H200)
Benzoic acid
HC7H502
CH
6.5 x 10
H30(aq) C7H502 (aq)
C-C
0
C2302(aq) H20U)
Acetic acid
HC2H302
1.8 x 10
H-0-0-CH3
H30() C2H302 (aq)
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