TABLE 13.3 Expected cost for each possible outcome And the demand probabilities are If the stocking The expected cost will be 2 3 prob. = .20 prob. =.40 prob. = .30 prob. =.10 level is 1 unit short .40(1) ($4,200) = $1,680 S=D 2 units short .30(2) 3 units short .10(3) $0 ($4,200) = $2,520 ($4,200) = $1,260 $5,460 1-unit excess .20(1) ($800) = $160 2 units short .10(2) ($4,200) = $840 S=D 1 unit short .30(1) ($4,200) = $1,260 $0 $2,260 2-unit excess .20(2) ($800) = $320 1-unit excess .40(1) ($800) = $320 S=D 1 unit short .10(1) ($4,200) = $420 $0 $1,060 2-unit excess .40(2) ($800) = $640 1-unit excess .30(1) ($800) = $240 3-unit excess .20(3) S=D ($800) = $480 $0 $1,360
TABLE 13.3 Expected cost for each possible outcome And the demand probabilities are If the stocking The expected cost will be 2 3 prob. = .20 prob. =.40 prob. = .30 prob. =.10 level is 1 unit short .40(1) ($4,200) = $1,680 S=D 2 units short .30(2) 3 units short .10(3) $0 ($4,200) = $2,520 ($4,200) = $1,260 $5,460 1-unit excess .20(1) ($800) = $160 2 units short .10(2) ($4,200) = $840 S=D 1 unit short .30(1) ($4,200) = $1,260 $0 $2,260 2-unit excess .20(2) ($800) = $320 1-unit excess .40(1) ($800) = $320 S=D 1 unit short .10(1) ($4,200) = $420 $0 $1,060 2-unit excess .40(2) ($800) = $640 1-unit excess .30(1) ($800) = $240 3-unit excess .20(3) S=D ($800) = $480 $0 $1,360
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
Related questions
Question
A Las Vegas supermarket bakery must decide how many wedding cakes to prepare for the upcoming weekend. Cakes cost $33 each to make, and they sell for $60 each. Unsold cakes are reduced
to half-price on Monday, and typically one-third of those are sold. Any that remain are donated to
a nearby senior center. Analysis of recent demand resulted in the following table:
Demand 0 1 2 3
Probability .15 .35 .30 .20
How many cakes should be prepared to maximize expected profit?
a. Use the ratio method.
b. Use the tabular method (see Table 13.3).

Transcribed Image Text:TABLE 13.3
Expected cost for each possible outcome
And the demand probabilities are
If the
stocking
The expected
cost will be
2
3
prob. = .20
prob. =.40
prob. = .30
prob. =.10
level is
1 unit short .40(1)
($4,200) = $1,680
S=D
2 units short .30(2)
3 units short .10(3)
$0
($4,200) = $2,520
($4,200) = $1,260
$5,460
1-unit excess .20(1)
($800) = $160
2 units short .10(2)
($4,200) = $840
S=D
1 unit short .30(1)
($4,200) = $1,260
$0
$2,260
2-unit excess .20(2)
($800) = $320
1-unit excess .40(1)
($800) = $320
S=D
1 unit short .10(1)
($4,200) = $420
$0
$1,060
2-unit excess .40(2)
($800) = $640
1-unit excess .30(1)
($800) = $240
3-unit excess .20(3)
S=D
($800) = $480
$0
$1,360
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