Confirm the expression given in Table 11B.1 for the moment of inertia of a linear ABC molecule. Hint: Begin by locating the centre of mass. Table 11B.1 Moments of inertia*I= 4m,Rm1. Diatomic moleculesm.RImu=R2. Triatomic linear rotorsI=m,R*+m_R*m.RR'm.m(m,R-m_R')mI= 2m, R*f(e)=1-cose, f,(@)=1+2cost; in each case, m is the total mass of the molecule.R.m3. Symmetric rotors1=2m, f,(@)R?me1=m,f,(e)R(m, +m,)f,(e)R*RmR(3m, +m, )R+6m, R+f,(@)}Rm4=2m,f,(@)R²1=mf,(@)Rm.mm1=4m,Rm.I_=2m,R² +2%¸R°²Rm.m.Rmc4. Spherical rotorsmI=#m,Rmm

In the figure above the distances of A,B and C from center of gravity of the molecule are shown.

Answered: Table 11B.1 Moments of inertia* I= 4m,R…

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