Table 1 R(Q) im(A) 100 0.008 200 0.004 330 0.012 1. Using Kirchhoff's Rules, construct enough mathematically independent equations to solve for the current of each resistor. Then calculate the % error between your measured and theoretical values for the current of each resistor. You MUST use Kirchhoff's Rules R1 R2 R3 AV1=5 it(A) % Error
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Determine,
The current in each resistors by using Kirchhoff's rules
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- Three resistors are made out of three different materials and have different (but uniform) cross sections. Resistor 1 has a circular cross section of radius 1.61 mm. Resistor 2 has a square cross section with a side length of 3.07 mm. The third resistor's cross section is a right triangle with two sides of length 2.59 mm. All of the resistors are 0.613 cm in length. Use the provided table of resistivities to calculate the resistance of each resistor. R₁ = R₂ = R3 = 6.95 Incorrect 443 0.086 Ω Ω Ω Material 1 Material 2 Material 3 2 0.00479 92.m 0.682 92-m 4.63 x 10-5 22-m 3Current and Resistance Problem 14: Resistivity in metals increases with temperature according to the equation ρ(T)=ρ0[1+α(T−T0)] where α is the temperature coefficient of resistivity, and ρ0 is the resistivity at reference temperature T0. For a particular wire, the temperature coefficient of resistivity is α=6.88×10−3∘C−1, and the resistivity is ρ0 = 5.41×10−7Ω⋅m at the reference temperature T0=232∘C. Part (b) What is this temperature T2, in degrees Celsius, for the wire described in the problem statement?Using Kirchhoff's rules, find the following. (&₁ = 70.2 V, &2 = 61.4 V, and 83 78.6 V.) = 4.00 ΚΩ = = b = Es a IR3 2.00 ΚΩ (a) the current in each resistor shown in the figure above X IRI Apply Kirchhoff's rules to write a set of simultaneous equations that can be solved for the current in each part of the circuit. mA X R₂ R₁ E₂ R3 f 3.00 ΚΩ d E₂ 3 R2 Apply Kirchhoff's rules to write a set of simultaneous equations that can be solved for the current in each part of the circuit. mA X Apply Kirchhoff's rules to write a set of simultaneous equations that can be solved for the current in each part of the circuit. mA
- Don't provide handwritten solution.Consider the following circuit diagram. The potential difference across the battery is 40.0 volts, and it supplies a current of 5.00 amperes to the circuit. There is a current of of 2.70 amperes flowing through R1. Resistor R2 has a resistance of 5.50 ohms. What is the resistance of R3? Answer in ohms to two decimal places, but do not include units in your answer.The resistance R of a conductor depends on its shape and physical dimensions and a property of the material called the resistivity p What does the resistivity of a material depend upon? Assuming that the resistivity of copper is a quarter of that of aluminium and that the density of copper is three times that of aluminimium, find the ratio of the masses of copper and aluminium wires with the same length and the same resistance but with different cross - sectional areas .
- An aluminum wire consists of the three segments shown in the following figure. The current in the top segment is 7.0 A (Figure 1) For each of these three segments, find the current I Express your answers using two significant figures separated by commas. ? Itop, Imid, Ibot = A Submit Request Answer Part B For each of these three segments, find the current density J. Express your answers using two significant figures separated by commas. HVα ΑΣφ ? Figure Jtop, Imid, Jbot = A/m? Submit Request Answer Part C 2.0 mm For each of these three segments, find the electric field E. 1.0 mm Express your answers using two significant figures separated by commas. 2.0 mm Ην ΑΣφ ? Etop, Emid, Ebot = V/mTwo wires have the same length and the same resistance but are made up of different materials. The resistivities of these materials are 1.38 Qm and 3.07 Qm. Obtain the ratio of the smaller cross-sectional area to the greater cross-sectional area. Number i Units