I need help with this problem and an explanation of this problem. ### Particle Displacement and Velocity CalculationThe displacement \( s \) (in meters) of a particle moving in a straight line is given by the equation of motion:\[ s = \frac{6}{t^2} \]where \( t \) is measured in seconds. To find the velocity \( v \) (in m/s) of the particle at specific times, we need to determine the derivative of the displacement equation with respect to time.### Calculation of VelocityLet's find the velocity at the following times: \( t = a \), \( t = 1 \), \( t = 2 \), and \( t = 3 \).1. **At \( t = a \):** \[ v = \boxed{ } \, \text{m/s} \]2. **At \( t = 1 \):** \[ v = \boxed{ } \, \text{m/s} \]3. **At \( t = 2 \):** \[ v = \boxed{ } \, \text{m/s} \]4. **At \( t = 3 \):** \[ v = \boxed{ } \, \text{m/s} \]To complete these calculations, remember to use the derivative of \( s = \frac{6}{t^2} \). The velocity \( v \) is given by:\[ v = \frac{ds}{dt} \]

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Answered: t=a v= t = 1 t = 2 t = 3 v = || V = m/s…

Math

Calculus

t=a v= t = 1 t = 2 t = 3 v = || V = m/s m/s m/s m/s

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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