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TA = The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m₁ = 95.0 kg and length L = 5.30 m is supported by two vertical massless strings. String A is attached at a distance d = 1.10 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500 kg is supported by the crane at a distance = 5.10 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s² for the magnitude of the acceleration due to gravity. Figure ▾ Part A String B d String A m2 mi x L Find TA, the tension in string A. Express your answer in newtons using three significant figures. View Available Hint(s) Hint 1. Choosing an axis Choose a rotation axis p about which to apply the requirement T, = 0. Since the system is in static equilibrium, the choice of rotation axis is arbitrary. However, there is a convenient choice of p that allows you to find Tд by eliminating the torque created by an unknown force. Hint 2. Find the torque around the convenient axis It is convenient to choose the rotation axis through the point at which string B is attached to the bar. With respect to this axis, the torque created by the tension in string B is zero. Which of the following is a correct expression for the total torque about this point? Στις m19L+m2gx-Tдd Tдd migL-m29x m19+m2gx - T₁d T₁d-m₁g -m2gx Submit Previous Answers Correct Hint 3. Applying the equilibrium condition For a static system, Σ Tp = 0. Solve for TA ΑΣΦ www ? N 1 of 1

TA = The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m₁ = 95.0 kg and length L = 5.30 m is supported by two vertical massless strings. String A is attached at a distance d = 1.10 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500 kg is supported by the crane at a distance = 5.10 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s² for the magnitude of the acceleration due to gravity. Figure ▾ Part A String B d String A m2 mi x L Find TA, the tension in string A. Express your answer in newtons using three significant figures. View Available Hint(s) Hint 1. Choosing an axis Choose a rotation axis p about which to apply the requirement T, = 0. Since the system is in static equilibrium, the choice of rotation axis is arbitrary. However, there is a convenient choice of p that allows you to find Tд by eliminating the torque created by an unknown force. Hint 2. Find the torque around the convenient axis It is convenient to choose the rotation axis through the point at which string B is attached to the bar. With respect to this axis, the torque created by the tension in string B is zero. Which of the following is a correct expression for the total torque about this point? Στις m19L+m2gx-Tдd Tдd migL-m29x m19+m2gx - T₁d T₁d-m₁g -m2gx Submit Previous Answers Correct Hint 3. Applying the equilibrium condition For a static system, Σ Tp = 0. Solve for TA ΑΣΦ www ? N 1 of 1

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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TA = The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m₁ = 95.0 kg and length L = 5.30 m is supported by two vertical massless strings. String A is attached at a distance d = 1.10 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500 kg is supported by the crane at a distance = 5.10 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s² for the magnitude of the acceleration due to gravity. Figure ▾ Part A String B d String A m2 mi x L Find TA, the tension in string A. Express your answer in newtons using three significant figures. View Available Hint(s) Hint 1. Choosing an axis Choose a rotation axis p about which to apply the requirement T, = 0. Since the system is in static equilibrium, the choice of rotation axis is arbitrary. However, there is a convenient choice of p that allows you to find Tд by eliminating the torque created by an unknown force. Hint 2. Find the torque around the convenient axis It is convenient to choose the rotation axis through the point at which string B is attached to the bar. With respect to this axis, the torque created by the tension in string B is zero. Which of the following is a correct expression for the total torque about this point? Στις m19L+m2gx-Tдd Tдd migL-m29x m19+m2gx - T₁d T₁d-m₁g -m2gx Submit Previous Answers Correct Hint 3. Applying the equilibrium condition For a static system, Σ Tp = 0. Solve for TA ΑΣΦ www ? N 1 of 1
Transcribed Image Text:TA = The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m₁ = 95.0 kg and length L = 5.30 m is supported by two vertical massless strings. String A is attached at a distance d = 1.10 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500 kg is supported by the crane at a distance = 5.10 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s² for the magnitude of the acceleration due to gravity. Figure ▾ Part A String B d String A m2 mi x L Find TA, the tension in string A. Express your answer in newtons using three significant figures. View Available Hint(s) Hint 1. Choosing an axis Choose a rotation axis p about which to apply the requirement T, = 0. Since the system is in static equilibrium, the choice of rotation axis is arbitrary. However, there is a convenient choice of p that allows you to find Tд by eliminating the torque created by an unknown force. Hint 2. Find the torque around the convenient axis It is convenient to choose the rotation axis through the point at which string B is attached to the bar. With respect to this axis, the torque created by the tension in string B is zero. Which of the following is a correct expression for the total torque about this point? Στις m19L+m2gx-Tдd Tдd migL-m29x m19+m2gx - T₁d T₁d-m₁g -m2gx Submit Previous Answers Correct Hint 3. Applying the equilibrium condition For a static system, Σ Tp = 0. Solve for TA ΑΣΦ www ? N 1 of 1
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