T7. A degree 37 polynomial has a remainder of 1 when divided by (x - 1). When it is divided by (x - 3) its remainder is 3. When it's divided by (x - 5) the remainder is 21. What is the remainder when it is divided by (x - 1)(x - 3) (x - 5)? Or(x) = 2x² - 7x+6 Or(x) = 63 There is not enough information to solve this question. Or(x) = (x − 1)(x − 3)(x – 5) -

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