t2 and y2 3 are two distinct solutions of the IVP t²y" – 4ty + 6y = 0, The functions yi %3D y(0) = 0, y'(0) = 0. Why does this not violate the Uniqueness and Existence Theorem

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 22RE
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t2y" – 4ty + 6y = 0,
The functions yı = t² and y2 = t³ are two distinct solutions of the IVP
y(0) = 0, y'(0) = 0. Why does this not violate the Uniqueness and Existence Theorem
%3D
%3D
Transcribed Image Text:t2y" – 4ty + 6y = 0, The functions yı = t² and y2 = t³ are two distinct solutions of the IVP y(0) = 0, y'(0) = 0. Why does this not violate the Uniqueness and Existence Theorem %3D %3D
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