T.A body weighing 10 kg is hung from a spring. A pull of 20 kg. wt. will stretch the spring to 10 cm. The body is pulled down to 20 cm below the static equilibrium position and then released. Find the displacement of the body from its equilibrium position at time t sec., the maximum velocity and the period of oscillation.

Q: 1. Explain why / f'(t) dt = f(b) – f (a). ||

A: Refer to image below.

Q: T √ radius 12 in Take a snapshot of time. X As the balloon inflates at 20 cubic inches per second,…

A: given balloon inflates rate is 20 cubic inches per seconds given  drdt=dVdt(14πr2)

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A:

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A: As per the guidelines I am supposed to solve only three sub parts of the given problem.

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A: y=∫sec x21t2+1dt.

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A: r''(t)=r'(t)-r'(t-1) So, r'(t)=r''(t)+r'(t-1) and  r'(t)=r(t)-r(t-1) So, r(t)=r'(t)+r(t-1) When t=1…

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A: We have to find the derivative

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A: