J- IBM SPSS Statistics ViewerataTransformInsertFormatAnalyzeGraphsUtilitiesExtensionsWindowHelpUPDATES AVAILABLEYesterday, 9:08 PMDo you want to restart to install these updates nowor try tonight?GETFILE='C:\Users\NATALIE.ROODMAN77\Downloads\Datal.sav'.DATASET NAME DataSetl WINDOW=FRONT.T-TEST GROUPS=Training (2 1)taset/MISSINGFANALYSISatistics/VARIABLES=JobSatent Sam/CRITERIA=CI (.95).- T-Test[DataSetl] C:\Users\NATALIE.ROODMAN77\Downloads\Datal.savGroup StatisticsStd. ErrorTrainingMeanStd. DeviationMeanJob SatisfactionTraining1213.81451.10919.10084No Training933.17261.06937.11089Independent Samples TestLevene's Test for Equality ofVariancest-test for Equality of Means95% Confidence Interval of theDifferenceMeanStd. ErrorSig.dfSig. (2-tailed)DifferenceDifferenceLowerUpperJob SatisfactionEqual variances.098.7554.262212.00064188.15060.34501.93875toassumedEqual variances not4.283201.451.00064188.1498834635.93742assumedIBM SPSS Statistics Processor is readyUnicode:ON10:48 PMVmHome Assignment .*Output1 [Docume...L Data1.sav [DataSet1...4/26/2022

The given output indicates the results obtained from a two-sample independent t-test.

Answered: - T-Test [Datasetl]…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose the mean height in inches of all 9th-grade students at one high school is estimated. the population's standard deviation is 3 inches. the heights of eight randomly selected students are, 74, 73 61,63,68,75,65 and 63. x̅ = ? margin of error at 90% confidence level = ? 90 percent confidence interval = ?_?
Report summary statistics for the two variables ‘Run_Pulse’ and ‘Rest_Pulse’ in the table below: Sample Size Minimum Maximum Mean Median Standard Deviation Standard Error Run_Pulse Rest_Pulse
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A manager of credit department at Selma stories wants to estimate the mean balance due on customers’ accounts. A Random sample of 25 accounts is drawn and it is found that their mean balance is 231.34$. While the mean balance changes from month to another, experience suggests that the stander deviation in the balances due is approximately constant is 84.37$.Find1- Construct 90% confidence Interval (C.L) for the mean balance of the customers’ accounts at Selma stories. And comment on the results.2- Construct 95% confidence Interval (C.L) for the mean balance of the customers’ accounts at Selma stories. And comment on the results.3- Without any computation, state what do you expect to happen if the confidence level changes from 90% to 99%4- What is the smallest sample size if the manager wants that the confidence length doesn’t exceed 60$ with confidence 95%
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True or False? A researcher wants to be sure the mean difference in the change in blood pressure has a margin of error no more than 5 points and the difference in the standard deviation between the mean blood pressure points from the first medication used to treat high blood pressure and the second medication used to treat high blood pressure is 14 points. The desired sample size required to ensure a 95% confidence interval for the proposed study used to compare the efficacy of two medications used to treat high blood pressure during a cross-over trial is n = 31.
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The gestation period of humans follows a normal distribution with a mean of 266 days and standard deviation of 16 days. If random samples of 15 pregnancies are studied, what is the mean and standard error of th sampling distribution of the sample mean? mean of the sampling distribution [ Choose ] standard error of the sampling distribution [ Choose ]
Construct a 95% confidence interval for the true mean of city mileage (MPG) of all cars with a manual transmission. Assume that MPG of cars with a manual transmission follows a normal distribution. Also, provide an interpretation of the confidence interval in context. Here is my work so far Manual and Automatic Transmission Total # of Cars = 1129 Total # of Automatic Trans. = 877 Total # of Manual Trans. = 252 Average (Auto) = 18.97948 Average (Manual) = 20.69841 Standard Deviation (Auto) = 8.390146 Standard Deviation (Manual) = 8.565189 Automatic Min: 8 Q1: 15 Median: 18 Q3: 21 Mode: =MAX(B2:B878) = 126 Manual Min: 11 Q1: 18 Median: 20 Q3: 24 Mode: 31
4. What is the range (sxs_) of the data values that would allow 55% of the data to fall within the mean observing symmetry? Draw the curve and show your complete solution. The Normal Distribution Activity For Data Set 2 A. 4. 110 ;..16 A 0. 150 1G ..500 Mean = 2.000 Variance = 4.5263 Standard Deviation = 2.1275 THE RANGE OF THE DATA UALUES 7. Sketch the second bell curve by showing the mean and standard deviation. UHEN -0,G TO PALL n E MERN ORsrenNE 0.16 x-t. . G A-t.t0 hart 1.6 315 : - t.10 ** 10. 945 - 6SIS x-.10 11.0025 The range of data values that will allow 55% of the data to fall within the mean of symmetry is 7.0625 and 10.3375 5. What is the variance of this data set? g? = (2.1546)? g? = 4.6423 Given that the standard deviation is 2.1546 and it is the square root of the variance, 8. What is the data value (raw score) associated with a standard score of 2.08? Determine the percentage greater than this score. Draw the curve and show your complete solution. the value of the…

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