[₂(t)] is(t) 圓 (t) dis(t) (t) [a(t)] 12(t) g(t)=[1 1 0 0] xa(t) [ra(t)] 9. Given the output y(t)==(24t-7e-3-9ef + 16) over the interval [0, 1], compute, if possible, the initial condition at t = 0. [(t)] 00-2 1 |x2(t) 00 0 1 23(t) 0 3 -2₁(t)

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