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It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 10³ m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020

It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 10³ m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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relate to the following scenario: It is found that 2.0 x 10-5 mol 222Rn (t/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 103 m3.
Transcribed Image Text:relate to the following scenario: It is found that 2.0 x 10-5 mol 222Rn (t/2 = 3.82 d, atom mass = 222) has seeped into a closed basement with a volume of 2.0 x 103 m3.
It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed %3D basement with a volume of 2.0 x 10³ m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020
Transcribed Image Text:It is found that 2.0 x 10-5 mol 222Rn (t1/2 = 3.82 d, atom mass = 222) has seeped into a closed %3D basement with a volume of 2.0 x 10³ m³. How many atoms of 222Rn will remain after 24 hours? A. 2.5 x 1018 B. 1.0 x 1019 C. 8.5 x 1018 D. 4.3 x 1020
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