t > 0 for the circuit below 1 kQ 1 k2 t=D0 10 V v1(t) =1/6 F vz(t)=1/16 µF

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Determine V1(t) for t>0 (Do not use Laplace Transform)
t> 0 for the circuit below
1 ka
1 ko
t= 0
10 V()
v;(t)=1/6F
v1(t) =1/6
vz(t)1/16 µF
Transcribed Image Text:t> 0 for the circuit below 1 ka 1 ko t= 0 10 V() v;(t)=1/6F v1(t) =1/6 vz(t)1/16 µF
Expert Solution
Step 1

The given circuit is shown in the figure below:

Electrical Engineering homework question answer, step 1, image 1

To find: v1(t) for t>0?

Step 2

At t<0, the switch is closed and the circuit is in steady-state (capacitor is open-circuited) as shown in the figure below:

Electrical Engineering homework question answer, step 2, image 1

So, the voltages will be:

v10-=1×1031×103+1×103×10=5 V=v10+v20-=0 V=v20+  across short path

As the capacitor voltage doesn't change instantaneously, so it will be the same for t=0- and t=0+.

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