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synthesis of Tris(ethylenediamine)nickel(1I) chloride dihydrate The equations of the preparation of [Ni(en)3]C12•2H2O are written: [Ni(H2O)6]Cl2 + 3 en → [Ni(en)3]C12•2H2O + 4 H20 For experiment used: - 6g of NiCl2-6H2O in 50 mL of H2O. - 20 ml of ethylenediamine. - Heat the solution until the solution volume becomes 25mL. - add two drops of ethylenediamine. Collect the product on a Büchner funnel and wash it with two 5 ml of ethanol. Note: I collected 9.518 grams of Tris(ethylenediamine)nickel(II) chloride dihydrate at the end of this experiment. Experimental Calculations: 1- Theoretical weight of the precipitate Molecular weight of the product X Weight of the reacted substance gm Molecular weight of the reacted substanc 2- Experimental weight of the precipitate = 9.518 g Experimental weight of the precipitat 3- Yield of the reaction = X100 = Theoretical weight of the precipitat 4- Percentage weight of each element = Atomic eight of the elements X no of its atom X100 = Molecular weight of the comple

synthesis of Tris(ethylenediamine)nickel(1I) chloride dihydrate The equations of the preparation of [Ni(en)3]C12•2H2O are written: [Ni(H2O)6]Cl2 + 3 en → [Ni(en)3]C12•2H2O + 4 H20 For experiment used: - 6g of NiCl2-6H2O in 50 mL of H2O. - 20 ml of ethylenediamine. - Heat the solution until the solution volume becomes 25mL. - add two drops of ethylenediamine. Collect the product on a Büchner funnel and wash it with two 5 ml of ethanol. Note: I collected 9.518 grams of Tris(ethylenediamine)nickel(II) chloride dihydrate at the end of this experiment. Experimental Calculations: 1- Theoretical weight of the precipitate Molecular weight of the product X Weight of the reacted substance gm Molecular weight of the reacted substanc 2- Experimental weight of the precipitate = 9.518 g Experimental weight of the precipitat 3- Yield of the reaction = X100 = Theoretical weight of the precipitat 4- Percentage weight of each element = Atomic eight of the elements X no of its atom X100 = Molecular weight of the comple

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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synthesis of Tris(ethylenediamine)nickel(1I) chloride dihydrate The equations of the preparation of [Ni(en)3]Cl2·2H2O are written: [Ni(H2O)6]C12 + 3 en > [Ni(en)3]C12·2H2O + 4 H2O For experiment used: - 6g of NiCl2-6H2O in 50 mL of H2O. - 20 ml of ethylenediamine. - Heat the solution until the solution volume becomes 25mL. - add two drops of ethylenediamine. - Collect the product on a Büchner funnel and wash it with two 5 ml of ethanol. Note: I collected 9.518 grams of Tris(ethylenediamine)nickel(I) chloride dihydrate at the end of this experiment. Experimental Calculations: 1- Theoretical weight of the precipitate Molecular weight of the product X Weight of the reacted substance gm Molecular weight of the reacted substanc 2- Experimental weight of the precipitate = 9.518 g Experimental weight of the precipitat Theoretical weight of the precipitat 3- Yield of the reaction X100 = 4- Percentage weight of each element = Atomic eight of the elements X no of its atom ×100 = Molecular weight of the comple
Transcribed Image Text:synthesis of Tris(ethylenediamine)nickel(1I) chloride dihydrate The equations of the preparation of [Ni(en)3]Cl2·2H2O are written: [Ni(H2O)6]C12 + 3 en > [Ni(en)3]C12·2H2O + 4 H2O For experiment used: - 6g of NiCl2-6H2O in 50 mL of H2O. - 20 ml of ethylenediamine. - Heat the solution until the solution volume becomes 25mL. - add two drops of ethylenediamine. - Collect the product on a Büchner funnel and wash it with two 5 ml of ethanol. Note: I collected 9.518 grams of Tris(ethylenediamine)nickel(I) chloride dihydrate at the end of this experiment. Experimental Calculations: 1- Theoretical weight of the precipitate Molecular weight of the product X Weight of the reacted substance gm Molecular weight of the reacted substanc 2- Experimental weight of the precipitate = 9.518 g Experimental weight of the precipitat Theoretical weight of the precipitat 3- Yield of the reaction X100 = 4- Percentage weight of each element = Atomic eight of the elements X no of its atom ×100 = Molecular weight of the comple
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