Sx*e-2x dx A -2x (2x +4x3 + 6x2 + 6x + 3) + C e-2r (2x* + 4x3 + 6x2 + 6x + 3) + C В - 4 x*e-2x - x3e-2x 3 3 x²e-2x xe-2x- e-2x + C 2. | x4 e-2x + x3e 3. .3-2x x²e-2x + 3 -2x e-2x + C - xe 2. )E None of the Above 3/2 C. B.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Integral Calculus: Integration by Parts (Shortcut Method)

3. *
Sx*e-2x dx
-2x
(2x* + 4x3 + 6x2 + 6x + 3) + C
4
e-2r
(2x* + 4x3 + 6x2 + 6x + 3) + C
4
C -x* e-2x – x³e-2x
2.
x²e-2* +
Xe-2x
3
-2x + C
-
D
x*e-2x + x³e-2.x
3.
3.
3.
x²e-2x +
4
3
-2x
xe
2.
-2x
2.
2.
4.
O A
O B
O D
O E None of the Above
Transcribed Image Text:3. * Sx*e-2x dx -2x (2x* + 4x3 + 6x2 + 6x + 3) + C 4 e-2r (2x* + 4x3 + 6x2 + 6x + 3) + C 4 C -x* e-2x – x³e-2x 2. x²e-2* + Xe-2x 3 -2x + C - D x*e-2x + x³e-2.x 3. 3. 3. x²e-2x + 4 3 -2x xe 2. -2x 2. 2. 4. O A O B O D O E None of the Above
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