Sx² 15 a. Find lim f(x). if x + 2 2. Let f(x) = } if x = 2 X→2 b. Find f(2). Is f(x) continuous at x = 2? с. Explain. d. Sketch a graph of f(x).
Sx² 15 a. Find lim f(x). if x + 2 2. Let f(x) = } if x = 2 X→2 b. Find f(2). Is f(x) continuous at x = 2? с. Explain. d. Sketch a graph of f(x).
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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---
### Problem 2
#### Let \( f(x) = \begin{cases}
x^2 & \text{if } x \neq 2 \\
5 & \text{if } x = 2
\end{cases} \)
**a. Find \( \lim_{{x \to 2}} f(x) \).**
**b. Find \( f(2) \).**
**c. Is \( f(x) \) continuous at \( x = 2 \)? Explain.**
**d. Sketch a graph of \( f(x) \).**
---
#### Explanation:
This problem involves a piecewise function \( f(x) \) which has different definitions depending on the value of \( x \). Specifically:
- For all \( x \) values not equal to 2, the function is defined as \( f(x) = x^2 \).
- For \( x \) equal to 2, the function takes on the value \( f(2) = 5 \).
#### Steps to Solve:
**a. Finding \( \lim_{{x \to 2}} f(x) \):**
To determine the limit of \( f(x) \) as \( x \) approaches 2, we consider the value of the function as \( x \) gets arbitrarily close to 2, but not equal to 2.
Since the function \( f(x) = x^2 \) for all \( x \neq 2 \):
\[ \lim_{{x \to 2}} f(x) = \lim_{{x \to 2}} x^2 = 2^2 = 4 \]
**b. Finding \( f(2) \):**
From the definition of the piecewise function:
\[ f(2) = 5 \]
**c. Is \( f(x) \) continuous at \( x = 2 \)? Explain:**
To determine if \( f(x) \) is continuous at \( x = 2 \), we check the following:
1. The limit of \( f(x) \) as \( x \) approaches 2 exists: \( \lim_{{x \to 2}} f(x) = 4 \)
2. \( f(2) \) is defined: \( f(2) = 5 \)
3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad3ee529-81b1-486a-8459-b4eea2f68af5%2F39cdd3bd-d731-4bb4-9e92-3097e2ad8ddc%2Frk6pn2r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Certainly! Below is the transcription and explanation for an educational website:
---
### Problem 2
#### Let \( f(x) = \begin{cases}
x^2 & \text{if } x \neq 2 \\
5 & \text{if } x = 2
\end{cases} \)
**a. Find \( \lim_{{x \to 2}} f(x) \).**
**b. Find \( f(2) \).**
**c. Is \( f(x) \) continuous at \( x = 2 \)? Explain.**
**d. Sketch a graph of \( f(x) \).**
---
#### Explanation:
This problem involves a piecewise function \( f(x) \) which has different definitions depending on the value of \( x \). Specifically:
- For all \( x \) values not equal to 2, the function is defined as \( f(x) = x^2 \).
- For \( x \) equal to 2, the function takes on the value \( f(2) = 5 \).
#### Steps to Solve:
**a. Finding \( \lim_{{x \to 2}} f(x) \):**
To determine the limit of \( f(x) \) as \( x \) approaches 2, we consider the value of the function as \( x \) gets arbitrarily close to 2, but not equal to 2.
Since the function \( f(x) = x^2 \) for all \( x \neq 2 \):
\[ \lim_{{x \to 2}} f(x) = \lim_{{x \to 2}} x^2 = 2^2 = 4 \]
**b. Finding \( f(2) \):**
From the definition of the piecewise function:
\[ f(2) = 5 \]
**c. Is \( f(x) \) continuous at \( x = 2 \)? Explain:**
To determine if \( f(x) \) is continuous at \( x = 2 \), we check the following:
1. The limit of \( f(x) \) as \( x \) approaches 2 exists: \( \lim_{{x \to 2}} f(x) = 4 \)
2. \( f(2) \) is defined: \( f(2) = 5 \)
3.
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