Sx² 15 a. Find lim f(x). if x + 2 2. Let f(x) = } if x = 2 X→2 b. Find f(2). Is f(x) continuous at x = 2? с. Explain. d. Sketch a graph of f(x).

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Certainly! Below is the transcription and explanation for an educational website:

---

### Problem 2

#### Let \( f(x) = \begin{cases} 
x^2 & \text{if } x \neq 2 \\ 
5 & \text{if } x = 2 
\end{cases} \)

**a. Find \( \lim_{{x \to 2}} f(x) \).**

**b. Find \( f(2) \).**

**c. Is \( f(x) \) continuous at \( x = 2 \)? Explain.**

**d. Sketch a graph of \( f(x) \).**

---

#### Explanation:

This problem involves a piecewise function \( f(x) \) which has different definitions depending on the value of \( x \). Specifically:

- For all \( x \) values not equal to 2, the function is defined as \( f(x) = x^2 \).
- For \( x \) equal to 2, the function takes on the value \( f(2) = 5 \).

#### Steps to Solve:

**a. Finding \( \lim_{{x \to 2}} f(x) \):**

To determine the limit of \( f(x) \) as \( x \) approaches 2, we consider the value of the function as \( x \) gets arbitrarily close to 2, but not equal to 2. 

Since the function \( f(x) = x^2 \) for all \( x \neq 2 \):
\[ \lim_{{x \to 2}} f(x) = \lim_{{x \to 2}} x^2 = 2^2 = 4 \]

**b. Finding \( f(2) \):**

From the definition of the piecewise function:
\[ f(2) = 5 \]

**c. Is \( f(x) \) continuous at \( x = 2 \)? Explain:**

To determine if \( f(x) \) is continuous at \( x = 2 \), we check the following:
1. The limit of \( f(x) \) as \( x \) approaches 2 exists: \( \lim_{{x \to 2}} f(x) = 4 \)
2. \( f(2) \) is defined: \( f(2) = 5 \)
3.
Transcribed Image Text:Certainly! Below is the transcription and explanation for an educational website: --- ### Problem 2 #### Let \( f(x) = \begin{cases} x^2 & \text{if } x \neq 2 \\ 5 & \text{if } x = 2 \end{cases} \) **a. Find \( \lim_{{x \to 2}} f(x) \).** **b. Find \( f(2) \).** **c. Is \( f(x) \) continuous at \( x = 2 \)? Explain.** **d. Sketch a graph of \( f(x) \).** --- #### Explanation: This problem involves a piecewise function \( f(x) \) which has different definitions depending on the value of \( x \). Specifically: - For all \( x \) values not equal to 2, the function is defined as \( f(x) = x^2 \). - For \( x \) equal to 2, the function takes on the value \( f(2) = 5 \). #### Steps to Solve: **a. Finding \( \lim_{{x \to 2}} f(x) \):** To determine the limit of \( f(x) \) as \( x \) approaches 2, we consider the value of the function as \( x \) gets arbitrarily close to 2, but not equal to 2. Since the function \( f(x) = x^2 \) for all \( x \neq 2 \): \[ \lim_{{x \to 2}} f(x) = \lim_{{x \to 2}} x^2 = 2^2 = 4 \] **b. Finding \( f(2) \):** From the definition of the piecewise function: \[ f(2) = 5 \] **c. Is \( f(x) \) continuous at \( x = 2 \)? Explain:** To determine if \( f(x) \) is continuous at \( x = 2 \), we check the following: 1. The limit of \( f(x) \) as \( x \) approaches 2 exists: \( \lim_{{x \to 2}} f(x) = 4 \) 2. \( f(2) \) is defined: \( f(2) = 5 \) 3.
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