switch (x) {case 1: w = y*z; break;case 2: w = y/z;case 3: w += z; break;case 5:case 6: w z; break;de fault: w = 2;}00000000004005e0 :rdx, Brex$0x6, &rdi200614 *0x200ab0 (, &rdi, 8)2005e0:2005e3:2005e7:2005e9:2005f0:2005£3:2005£7:2005f8:2005fb:2005fd:200600:200602:200607:20060a:20060b:200610:200613:200614:200619:movcmpjajmpqπουimulretqπου0x200ad00x200ad80x200ae00x200c8cqtoidivBrsi, Braxrdx, Braxretqmovsubretqπουretq8rsi, Brax8rcxjmp 200607 που$0x1, Seaxaddsrcx, trax$0x1, Seax8rdx, Brax$0x2, SeaxWrite the results of the command (gdb) x /10xg 0x200aa0Address Data (in 8-byte chunk in hexadecimal number, put in XX for unknown)0x200aa00x200aa80x200ab00x200ab80x200ac00x200ac8

The specific command you mentioned, "x /10xg 0x200aa0", is used in GDB to examine the memory…

switch (x) { case 1: w = y*z; break; case 2: w = y/z; case 3: W += z; break; case 5: case 6: w z; break; default: W= 2; } 00000000004005e0 : rdx, &rex $0x6, &rdi 200614 *0x200ab0 (, Brdi, 8) 2005e0: 2005e3: 2005e7: 2005e9: 2005£0: 2005£3: 2005£7: 2005£8: 2005fb: 2005fd: 200600: 200602: 200607: 20060a: 20060b: 200610: 200613: 200614: 200619: 0x200ab8 0x200ac0 0x200ac8 mov cmp ja jmpq mov imul retq που 0x200ad0 0x200ad8 0x200ae0 0x200ae8 cqto idiv 8rsi, rax 8rdx, Brax που add retq που sub retq mov retq Brsi, Brax Brex jmp 200607 $0x1, Seax srcx, trax $0x1, Seax 8rdx, Brax Write the results of the command (gdb) x /10xg 0x200aa0 Address Data (in 8-byte chunk in hexadecimal number, put in XX for unknown) 0x200aa0 0x200aa8 0x200ab0 $0x2, Seax

switch (x) { case 1: w = yz; break; case 2: w = y/z; case 3: W += z; break; case 5: case 6: w z; break; default: W= 2; } 00000000004005e0 : rdx, &rex $0x6, &rdi 200614 0x200ab0 (, Brdi, 8) 2005e0: 2005e3: 2005e7: 2005e9: 2005£0: 2005£3: 2005£7: 2005£8: 2005fb: 2005fd: 200600: 200602: 200607: 20060a: 20060b: 200610: 200613: 200614: 200619: 0x200ab8 0x200ac0 0x200ac8 mov cmp ja jmpq mov imul retq που 0x200ad0 0x200ad8 0x200ae0 0x200ae8 cqto idiv 8rsi, rax 8rdx, Brax που add retq που sub retq mov retq Brsi, Brax Brex jmp 200607 $0x1, Seax srcx, trax $0x1, Seax 8rdx, Brax Write the results of the command (gdb) x /10xg 0x200aa0 Address Data (in 8-byte chunk in hexadecimal number, put in XX for unknown) 0x200aa0 0x200aa8 0x200ab0 $0x2, Seax

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Home B Announcements - IT-140-J6182 zy Section 3.2 - IT 140: Introduction b Answered: Write an if-else stater + 8 https://learn.zybooks.com/zybook/SNHUIT140V3/chapter/3/section/2 = zyBooks My library > IT 140: Introduction to Scripting v3 home > 3.2: If-else statement E zyBooks catalog e Help/FAQ 8 Jose Roque Write an if-else statement with multiple branches. If year is 2101 or later, print "Distant future" (without quotes). Otherwise, if year is 2001 or greater, print "21st century". Otherwise, if year is 1901 or greater, print "20th century". Else (1900 or earlier), print "Long ago". Sample output with input: 1776 Long ago 247772.2002516.gx3zgy7 1 year = int(input ()) 2 1 test 3' Your solution goes here ''" passed 4 All tests passed Activate Windows Go to Settings to activate Windows. Run 10:25 PM P Type here to search 83°F Mostly clear 7/19/2021 DIDI 近

Shell Scripting: Write the output when the input is 40: echo -n "Enter any number:" read n if [ $n -eq 30 ] 11 [ $n -gt 50 ] then echo "1" else echo "2" fi
Listing 11-05.php 1k?php 2 switch ($artType) { Listing 11-06.php case "PT": Soutput break; 4 "Painting"; 5 6 case "SC": $output break; 7 "Sculpture"; 8 9. default: 10 $output "Other"; 11 } 12 // equivalent 13 if ($artType Şoutput 15 else if ($artType $output "PT") "Painting"; "SC") "Sculpture"; 14 == 16 17 else 18 $output "Other"; %3D 19 20 21 //extra line for demo 22 echo Soutput; 23 ?> Read through and understand this code line by line. The variable $artType is not defined, you can hardcode its value. Make this program produce a meaningful output, provide source code and the output.
Command line arguments are passed to int main(int argc, char** argv) as arguments argc and argv. You should assume that argc is at ebp+8 and argv is at ebp+12. 00000000 <what>: 0: push %ebp 1: mov %esp,%ebp 3: sub $0x10,%esp 6: mov 0x8(%ebp),%eax 9: add $0x4,%eax c: mov %eax,-0x4(%ebp) f: mov 0x8(%ebp),%eax 12: imul 0xc(%ebp),%eax 16: mov %eax,-0x8(%ebp) 19: mov 0x8(%ebp),%eax 1c: sub 0xc(%ebp),%eax 1f: mov %eax,-0xc(%ebp) 22: mov -0x4(%ebp),%edx 25: mov -0x8(%ebp),%eax 28: add %eax,%edx 2a: mov -0xc(%ebp),%eax 2d: add %edx,%eax 2f: leave 30: ret00000031 <main>: 31: lea 0x4(%esp),%ecx 35: and $0xfffffff0,%esp 38: pushl -0x4(%ecx) 3b: push %ebp 3c: mov %esp,%ebp 3e: push %ebx 3f: push %ecx 40: sub $0x10,%esp 43: mov %ecx,%ebx 45: mov 0x4(%ebx),%eax 48: add $0x4,%eax 4b: mov (%eax),%eax 4d: sub…
#include <iostream>#include <pthread.h>#include <stdlib.h> #define TOTAL_THREADS 4 int count;pthread_mutex_t the_mutex; // phread mutex variable - initialize here if using the initializer macro void* myFunction(void* arg){int actual_arg = *((int*) arg);for(unsigned int i = 0; i < 10; ++i) {// TODO:// Use a Pthread mutex to control// access to the critical region. // Beginning of the critical regioncount++;std::cout << "Thread #" << actual_arg << " count = " << count << std::endl; // End of the critical region// TODO:// Relinquish access to the Pthread mutex// since critical region is complete. // Random wait - This code is just to ensure that the threads// show data sharing problemsint max = rand() % 100000;for (int x = 0; x < max; x++);// End of random wait code}pthread_exit(NULL);} int main(){int rc[TOTAL_THREADS];pthread_t ids[TOTAL_THREADS];int args[TOTAL_THREADS];// TODO: Initialize the pthread mutex here if using the…
Extra Credit (Optional) https://leam.zybooks.com/zybook/UCMERCEDCSE019FariasSummer loci My library> CSE 019: Introduction to Computing home > 2.9: Math module n @ W S Check CHALLENGE ACTIVITY 478822 3415480.qx3zqy7 Jump to level 1 2.9.2: Math functions. 6 Your code goes here 7 # Next 3 Write the code that computes: z = |x+y| Note: Use dot notation to access an object in the math module. Ex: The constant pi is accessed via math.pi. 1 import math 2 3 x = float(input())] 4 y float(input()) 8 print (f'(z:.2f}') # This will output only 2 decimal places. 9 E D IDI $ 4 Q Search R F % LO Section 29 CSE 019 Introduct X 2023/chapter/2/section/9 5 Ombuds UC Merced|(209) 228-4410 T ◄O G 6 no U & 80 Y 7 EzyBooks catalog H 18 4+ 2 N 19 144 8 00 J ( - Help/FAQ DELEANOR LASHUNI HASTI 9 A 18 M Amazon ► 11 K Feedback? O M-D E- ENG P A 1
write a windows32 assembly language program that calculates the Catalan Number for some positive integer that the user enters. The main (_MainProc) procedure should: accept, from the user, a positive integer. Guard against non-positive integers being entered using a loop, call the catalan sub-procedure using the cdecl protocol, receive the results of the sub-procedure, and display the results in a meaningful way to the user. The catalan sub-procedure should: calculate, for a given n, (2n)!/((n+1)!n!) by calling the factorial sub-procedure for each term where needed, calculating the result, and return the value back to the calling procedure. The factorial sub-procedure should: calculate the factorial of a given value m. return the value back to the calling procedure.
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