Switch the order of integration of the following integrals, then evaluate: ƒ ƒ x sin(y²) dydx = x=0 y=x 08- DS- 04- 02- 02 05 08 1

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
## Switch the Order of Integration

Switch the **order of integration** of the following integrals, then **evaluate**:

\[ \int_{x=0}^{1} \int_{y=x}^{1} x \sin(y^3) \, dy \, dx = \]

### Steps to switch the order of integration:

1. **Identify the original limits:**
   - For \( x \) from 0 to 1.
   - For \( y \) from \( x \) to 1.

2. **Graphical representation:**
   The graph depicts the region of integration in the \( xy \)-plane, represented by a triangular region bounded as follows:
   - The x-axis, from 0 to 1.
   - The line \( y = x \).
   - The vertical line \( y = 1 \).

3. **Rewriting the integral with switched order:**
   To switch the order of integration, express the region in terms of \( y \) first and then \( x \):
   - \( y \): from 0 to 1
   - \( x \): from 0 to \( y \)

Thus, the integral becomes:
\[ \int_{y=0}^{1} \int_{x=0}^{y} x \sin(y^3) \, dx \, dy \]

### Evaluate the integral after switching

1. **Inner integral evaluation:**
   \[\int_{x=0}^{y} x \sin(y^3) \, dx\]
   \( x \sin(y^3) \) is treated as a constant with respect to \( x \):
   \[ \sin(y^3) \int_{x=0}^{y} x \, dx = \sin(y^3) \left[ \frac{x^2}{2} \right]_{0}^{y} = \sin(y^3) \cdot \frac{y^2}{2} \]

2. **Result of the inner integral:**
   \[ \frac{y^2}{2} \sin(y^3) \]

3. **Outer integral evaluation:**
   \[\int_{y=0}^{1} \frac{y^2}{2} \sin(y^3) \, dy\]

   - Let \( u = y^3 \), hence \( du = 3y^2 \,
Transcribed Image Text:## Switch the Order of Integration Switch the **order of integration** of the following integrals, then **evaluate**: \[ \int_{x=0}^{1} \int_{y=x}^{1} x \sin(y^3) \, dy \, dx = \] ### Steps to switch the order of integration: 1. **Identify the original limits:** - For \( x \) from 0 to 1. - For \( y \) from \( x \) to 1. 2. **Graphical representation:** The graph depicts the region of integration in the \( xy \)-plane, represented by a triangular region bounded as follows: - The x-axis, from 0 to 1. - The line \( y = x \). - The vertical line \( y = 1 \). 3. **Rewriting the integral with switched order:** To switch the order of integration, express the region in terms of \( y \) first and then \( x \): - \( y \): from 0 to 1 - \( x \): from 0 to \( y \) Thus, the integral becomes: \[ \int_{y=0}^{1} \int_{x=0}^{y} x \sin(y^3) \, dx \, dy \] ### Evaluate the integral after switching 1. **Inner integral evaluation:** \[\int_{x=0}^{y} x \sin(y^3) \, dx\] \( x \sin(y^3) \) is treated as a constant with respect to \( x \): \[ \sin(y^3) \int_{x=0}^{y} x \, dx = \sin(y^3) \left[ \frac{x^2}{2} \right]_{0}^{y} = \sin(y^3) \cdot \frac{y^2}{2} \] 2. **Result of the inner integral:** \[ \frac{y^2}{2} \sin(y^3) \] 3. **Outer integral evaluation:** \[\int_{y=0}^{1} \frac{y^2}{2} \sin(y^3) \, dy\] - Let \( u = y^3 \), hence \( du = 3y^2 \,
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