Answered: swap_nums seems to work, but not…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

swap_nums seems to work, but not swap_pointers. Fix it.

#include <stdio.h>
void swap_nums(int *x, int *y)
{
int tmp;
tmp = *x;
*x = *y;
*y = tmp;
}
void swap_pointers(char *x, char *y)
{
char *tmp;
tmp = x;
x = y;
y = tmp;
}
int main()
{
int a,b;
char *s1,*s2;
a = 3; b=4;
swap_nums(&a,&b);
printf("a is %d\n", a);
printf("b is %d\n", b);
s1 = "I should print second";
s2 = "I should print first";
swap_pointers(s1,s2);
printf("s1 is %s\n", s1);
printf("s2 is %s\n", s2);
return 0;

}

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