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Survival Status and Heart Rate in the ICU The dataset ICUAdmissions contains information on a sample of 200 patients being admitted to the Intensive Care Unit (ICU) at a hospital. One of the variables is HeartRate and another is Status which indicates whether the patient lived (Status = 0) or died (Status = 1). The computer output below shows the details of a test to determine whether mean heart rate is different between patients who lived and died. (You should not do any computations. State the hypotheses based on the output, read the p-value off the output, and state the conclusion). %3D Two-sample T for HeartRate Status Mean StDev SE Mean 160 98.5 27.0 2.1 1 40 100.6 26.5 4.2 Difference = μ (0 )-μ (1) Estimate for difference:-2.12 95 % Cl for difference: (- 11.53, 7.28) T-Test of difference = 0 (vs not :): T-Value - 0.45 %3D P-Value = 0.653 DF = 60

Survival Status and Heart Rate in the ICU The dataset ICUAdmissions contains information on a sample of 200 patients being admitted to the Intensive Care Unit (ICU) at a hospital. One of the variables is HeartRate and another is Status which indicates whether the patient lived (Status = 0) or died (Status = 1). The computer output below shows the details of a test to determine whether mean heart rate is different between patients who lived and died. (You should not do any computations. State the hypotheses based on the output, read the p-value off the output, and state the conclusion). %3D Two-sample T for HeartRate Status Mean StDev SE Mean 160 98.5 27.0 2.1 1 40 100.6 26.5 4.2 Difference = μ (0 )-μ (1) Estimate for difference:-2.12 95 % Cl for difference: (- 11.53, 7.28) T-Test of difference = 0 (vs not :): T-Value - 0.45 %3D P-Value = 0.653 DF = 60

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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State the null and alternative hypotheses. Use subscripts 1 for patients who live (Status = 0) and 2 (Status 1) for patients who die. :: < : > :: u :: :: p :: P1 : P2 :: p :: x1 :: x2 : P2 :: r .. : P1 Ho: vs Ha: Give the p-value. Enter the exact answer. p-value ::
Transcribed Image Text:State the null and alternative hypotheses. Use subscripts 1 for patients who live (Status = 0) and 2 (Status 1) for patients who die. :: < : > :: u :: :: p :: P1 : P2 :: p :: x1 :: x2 : P2 :: r .. : P1 Ho: vs Ha: Give the p-value. Enter the exact answer. p-value ::
Survival Status and Heart Rate in the ICU The dataset ICUAdmissions contains information on a sample of 200 patients being admitted to the Intensive Care Unit (ICU) at a hospital. One of the variables is HeartRate and another is Status which indicates whether the patient lived (Status = 0) or died (Status mean heart rate is different between patients who lived and died. (You should not do any computations. State the hypotheses based on the output, read the p-value off the output, and state the conclusion). 1). The computer output below shows the details of a test to determine whether Two-sample T for HeartRate Status N Мean StDev SE Mean 160 98.5 27.0 2.1 1 40 100.6 26.5 4.2 Difference μ (0)-μ (1) Estimate for difference: – 2.12 95 % Cl for difference: ( – 11.53, 7.28) T-Test of difference = 0 (vs not = ): T-Value - 0.45 P-Value 0.653 DF 60
Transcribed Image Text:Survival Status and Heart Rate in the ICU The dataset ICUAdmissions contains information on a sample of 200 patients being admitted to the Intensive Care Unit (ICU) at a hospital. One of the variables is HeartRate and another is Status which indicates whether the patient lived (Status = 0) or died (Status mean heart rate is different between patients who lived and died. (You should not do any computations. State the hypotheses based on the output, read the p-value off the output, and state the conclusion). 1). The computer output below shows the details of a test to determine whether Two-sample T for HeartRate Status N Мean StDev SE Mean 160 98.5 27.0 2.1 1 40 100.6 26.5 4.2 Difference μ (0)-μ (1) Estimate for difference: – 2.12 95 % Cl for difference: ( – 11.53, 7.28) T-Test of difference = 0 (vs not = ): T-Value - 0.45 P-Value 0.653 DF 60
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