surprised? (d) How many points should you expect the player to score if all of these are 3-point shots? (e) If this player randomly takes half of the shots from 3-point range and half from 2-point range and makes both with 25% chance, how many points should you expect the player to score? (Type an imeyer vi a utcimal.)
surprised? (d) How many points should you expect the player to score if all of these are 3-point shots? (e) If this player randomly takes half of the shots from 3-point range and half from 2-point range and makes both with 25% chance, how many points should you expect the player to score? (Type an imeyer vi a utcimal.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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I need help with d and e

Transcribed Image Text:**Title: Understanding Binomial Probability in Basketball**
**Introduction:**
In this exercise, we explore the application of a binomial model to predict basketball shooting performance. A hypothetical scenario is provided where a basketball player takes 20 field shots during a game with a 25% success rate.
**Exercise Details:**
1. **Assumptions for a Binomial Model:**
- The player attempts 20 shots, each shot is independent with a 25% probability of success.
- Assumptions:
- Each shot is an independent event.
- The probability of making a shot remains constant at 25% for each attempt.
- These assumptions are reasonable under controlled conditions but may vary in a real game scenario due to factors like player fatigue or defensive pressure.
2. **Expected Number of Baskets:**
- You can calculate the expected number of successful shots by multiplying the total attempts by the probability:
- \( E(x) = n \times p = 20 \times 0.25 = 5 \) baskets.
3. **Surprise Factor for Success Over 11 Shots:**
- Given the low success probability, hitting more than 11 shots is unlikely.
- Assessment:
- The result is surprising: The probability of this occurring is 0.001.
- Answer choice:
- **B. Yes, you should be surprised because the probability of this occurring is 0.001.**
4. **Expected Points Scored with 3-Point Shots:**
- If all successful shots are 3-pointers:
- Expected points = \( 3 \times \text{Expected baskets} = 3 \times 5 = 15 \) points.
5. **Mixed Range Shots Calculation:**
- If half of the shots are taken from 3-point range and half from 2-point range:
- Both shot types have a 25% success rate.
- Calculate expected points:
- \( \text{3-point shots: } 10 \times 0.25 \times 3 = 7.5 \)
- \( \text{2-point shots: } 10 \times 0.25 \times 2 = 5 \)
- Total expected points = \( 7.5 + 5 = 12.5 \) points.
**Conclusion:**
This exercise illustrates the use of binomial probability to estimate
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