Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of c so that thefollowing is true.P(-csZ

We have given that Z follows standard normal distribution that is, Z ~ N( 0, 1 ). Note: P-value…

Answered: Suppose Z follows the standard normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Components that are critical for the operation of electrical systems are replaced immediately upon failure. Suppose that the life time of a certain such component can be modeled by a lognormal distribution with mean u = 500 hours and standard deviation o = 100 hours. Find the median life time of the components. (Use four digits after the decimal point, e.g. 0.1234) Hint: You need to start by finding the values of 0 and w?. Type your answer..
Terri Vogel, an amateur motorcycle racer, averages 129.52 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation of 2.28 seconds . The distribution of her race times is normally distributed. We are interested in one of her randomly selected laps. (Source: log book of Terri Vogel) Let X be the number of seconds for a randomly selected lap. Round all answers to 4 decimal places where possible. b. Find the proportion of her laps that are completed between 128.81 and 131.26 seconds c. The fastest 3% of laps are under ____ seconds. d. The middle 80% of her laps are from __________ seconds to __________ seconds.
All one problem. Show work and formulas and calculations please. Thank you. For a standard normal distribution, find:P(-1.46 < z < 1.74) ______ Write an equation in the form y=mx+by=mx+b for the following table: x y -10 -49 -8 -37 -6 -25 -4 -13 -2 -1 0 11 2 23 4 35 y=______ What value completes the probability distribution below? X 0 1 2 3 4 5 P(X) 1/5 17/120 1/6 1/6 1/8 −19/120 61/280 17/120 5/24 1/5
Terri Vogel, an amateur motorcycle racer, averages 129.14 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation of 2.28 seconds . The distribution of her race times is normally distributed. We are interested in one of her randomly selected laps. (Source: log book of Terri Vogel) Let X be the number of seconds for a randomly selected lap. Round all answers to 4 decimal places where possible.b. Find the proportion of her laps that are completed between 131.08 and 134.03 seconds. ___________________c. The fastest 2% of laps are under seconds.____________________d. The middle 70% of her laps are from ____ seconds to ____ seconds.
In each part, find the area under the standard normal curve that lies between the specied z-scores, sketch a standard normal curve, and shade the area of interest. a. -1 and 1b. -2 and 2c. -3 and 3
Find the z-score that has 68.4% of the distribution's area to its right. Can you also give the steps in the calculator? TI-84
The price of Bank of Florida shares at the end of trading each day for the last year followed a Normal Distribution with the following parameters. μ = 177 and o² = 4.84 a. What is the variable of interest?
Find fo.10 for F distribution with (2,4) degrees of freedom. fo.10 (Round the answer to 2 decimal places)
Use a table of cumulative areas under the normal curve to find the z-score that corresponds to the given cumulative area. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. 0.05 Click to view page 1 of the table. Click to view page 2 of the table. The cumulative area corresponds to the z-score of (Round to three decimal places as needed.) Standard Normal Table (Page 1) Z 0.09 0.08 0.07 0.06 0.05 0.04 0.03 0.02 0.01 0.00 -3.4 0.0002 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 -3.3 0.0003 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0005 0.0005 0.0005 - 3.2 0.0005 0.0005 0.0005 0.0006 0.0006 0.0006 0.0006 0.0006 0.0007 0.0007 - 3.1 0.0007 0.0007 0.0008 0.0008 0.0008 0.0008 0.0009 0.0009 0.0009 0.0010 -3.0 | 0.0010 0.0010 0.0011 0.0011 0.0011 0.0012 0.0012 0.0013 0.0013 0.0013 -2.9 0.0014 0.0014 0.0015…
In each part, find the area under the standard normal curve that lies between the specified z-score, sketch a standard normal curve, and shade the area of interest. b. -2 and 2 c. - 3 and 3 a. - 1 and 1 a. Find the area under the standard normal curve that lies between - 1 and 1, sketch a standard normal curve, and shade the area of interest. The area under the standard normal curve that lies between - 1 and 1 is (Type an integer or decimal rounded to four decimal places as needed.)
Find to.20 for T distribution with 29 degrees of freedom. to.20 (Round the answer to 3 decimal places)
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is less than 0.89 and draw a sketch of the region. Sketch the region. Choose the correct graph below. O A. -0.89 The probability is (Round to four decimal places as needed.) B. -0.89 0.89 C. A -0.89 D. 0.89

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Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of c so that the following is true. P(-csZsc)=0.9181 Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.