Suppose you. have 185mL of a buffer that is 0.160 M in both formic acid (HCOOH) and its conjugate base (HCOO) Calculate the maximum volume of 0.180 M HCl that can be added to the buffer before its buffering capacity is lost.

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Im trying to solve for x. is there a better way to solve for x without factoring? Im bad attaht and always mess it up during tests

pka of acetic acid is 4.76
Suppose you have 185mL of a buffer that is 0.160 M
in both formic acid (HCOOH) and its conjugate base (HCOO)
Calculate the maximum volume of 0.180 M HCl that
can be added to the buffer before its buffering capacity
is lost.
In
Нcoo
HOCH
= 4.76 + log (0.160
PH = pka + log
PH
[нсоот у
[H COOH
21
so pH = 4.76
Then MXV = 0.160 × 185 = 29.6
29.6-X
(29.6-X)
-0.1
>
Transcribed Image Text:pka of acetic acid is 4.76 Suppose you have 185mL of a buffer that is 0.160 M in both formic acid (HCOOH) and its conjugate base (HCOO) Calculate the maximum volume of 0.180 M HCl that can be added to the buffer before its buffering capacity is lost. In Нcoo HOCH = 4.76 + log (0.160 PH = pka + log PH [нсоот у [H COOH 21 so pH = 4.76 Then MXV = 0.160 × 185 = 29.6 29.6-X (29.6-X) -0.1 >
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