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Suppose you were required to create a reasonably detailed estimate for developing a new student information and admissions system at a local college. Your firm's programmers average 6 function points on a person-month basis. After speaking with representatives from the college, you know that their request is based on the following screen requirements: inputs (4), outputs (7), interfaces (12), queries (20), and files (16). Further, we have determined that the relative complexity of each of these functions is as follows: inputs (low), outputs (medium), interfaces (high), queries (medium), and files (medium). Using this information and the following table, calculate the number of function points for this project. Function Number of Inputs Number of Outputs Number of Interfaces Number of Queries Number of Files 3 x 2 x 1 x 4x 4x Low = = Complexity Weighting Medium 6 x 6 x 3 x 8 x 6 x 9x 10 X 5 X 12 X 8x High Total

Suppose you were required to create a reasonably detailed estimate for developing a new student information and admissions system at a local college. Your firm's programmers average 6 function points on a person-month basis. After speaking with representatives from the college, you know that their request is based on the following screen requirements: inputs (4), outputs (7), interfaces (12), queries (20), and files (16). Further, we have determined that the relative complexity of each of these functions is as follows: inputs (low), outputs (medium), interfaces (high), queries (medium), and files (medium). Using this information and the following table, calculate the number of function points for this project. Function Number of Inputs Number of Outputs Number of Interfaces Number of Queries Number of Files 3 x 2 x 1 x 4x 4x Low = = Complexity Weighting Medium 6 x 6 x 3 x 8 x 6 x 9x 10 X 5 X 12 X 8x High Total

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Example 3: Suppose you were required to create a reasonably detailed estimate for developing a new student information and admissions system at a local college. Your firm's programmers average 6 function points on a person-month basis. After speaking with representatives from the college, you know that their request is based on the following screen requirements: inputs (4), outputs (7), interfaces (12), queries (20), and files (16). Further, we have determined that the relative complexity of each of these functions is as follows: inputs (low), outputs (medium), interfaces (high), queries (medium), and files (medium). Using this information and the following table, calculate the number of function points for this project. Function Number of Inputs Number of Outputs Number of Interfaces Number of Queries Number of Files 3 x 2 X 1 x 4 x 4 x Low = = = Complexity Weighting Medium 6 X 6 x 3 x 8 x 6 x = = 9x 10 X 5x 12 X 8 x High |||| |||| Total
Transcribed Image Text:Example 3: Suppose you were required to create a reasonably detailed estimate for developing a new student information and admissions system at a local college. Your firm's programmers average 6 function points on a person-month basis. After speaking with representatives from the college, you know that their request is based on the following screen requirements: inputs (4), outputs (7), interfaces (12), queries (20), and files (16). Further, we have determined that the relative complexity of each of these functions is as follows: inputs (low), outputs (medium), interfaces (high), queries (medium), and files (medium). Using this information and the following table, calculate the number of function points for this project. Function Number of Inputs Number of Outputs Number of Interfaces Number of Queries Number of Files 3 x 2 X 1 x 4 x 4 x Low = = = Complexity Weighting Medium 6 X 6 x 3 x 8 x 6 x = = 9x 10 X 5x 12 X 8 x High |||| |||| Total
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