FemaleMaleSuppose you were able to take a random sample of 100 females from the same population of females as the sample of2,128. How would the sample standard deviation estimate for these 100 sample blood lead level measurements (S100)compare, in value, to the sample standard deviation of the original 2,128 blood lead level measurements (1.16microgram/dL)?S100 > 1.16O 5100 should be similar in value to 1.16, but there is no way to predict exactly how the two estimates will compares nonumericallyS100 <1.16S100 = 1.16/sqrt(100) 1. Data from the year 2012 National Health and Nutrition Examination Survey (NHANES) survey includes laboratorymeasurements on a random sample of more than four thousand 18-65 year old persons in the United States. Thefollowing boxplots display the distribution of blood lead levels (mg/dL) for this sample, separately for males and females.The accompanying tables display summary statistics of the sample values.Blood Lead Levels by Biological SexNHANES Laboratory Data, 2012Females (n=2,128)Males (n=1,892)20ž: 1.27s: 1.16Range: 0.18 – 15.2ž: 1.97s: 1.61Range: 0.18 -22.3Percentiles:Percentiles:5a: 0.3725th: 0.6250th: 0.955th : 0.6025th: 1.0050: 1.6075h: 1.595th: 3.1075th: 2.495th: 4.6O COO ODO O OODOL15Blood Lead Level (micrograms/dl)

Given : Here the sample standard deviation = 1.16 The formula for calculating the sample standard…

Suppose you were able to take a random sample of 100 females from the same population of females as the sample of 2,128. How would the sample standard deviation estimate for these 100 sample blood lead level measurements (5100) compare, in value, to the sample standard deviation of the original 2,128 blood lead level measurements (1.16 microgram/dL)? S100 > 1.16 5100 should be similar in value to 1.16, but there is no way to predict exactly how the two estimates will compare numerically O S100 <1.16 5100 - 1.16/sqrt(100)

Suppose you were able to take a random sample of 100 females from the same population of females as the sample of 2,128. How would the sample standard deviation estimate for these 100 sample blood lead level measurements (5100) compare, in value, to the sample standard deviation of the original 2,128 blood lead level measurements (1.16 microgram/dL)? S100 > 1.16 5100 should be similar in value to 1.16, but there is no way to predict exactly how the two estimates will compare numerically O S100 <1.16 5100 - 1.16/sqrt(100)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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how did you get the standard deviation of 4.8567 on the solution above?