### Understanding Pulley Systems and Their Applications in Lifting#### Scenario:Suppose you used an ideal pulley of the type shown in image (c) in the figure below to support a car engine of mass 225 kg. The pulley system's mass is 5.90 kg.#### Figure Description:The figure includes three types of pulley systems:1. **Image (a):** A single pulley system (Mechanical Advantage, MA = 2) - The force \( T \) is shown acting upward at both ends of the rope.2. **Image (b):** A dual pulley system (MA = 3) - The force \( T \) is distributed among three segments of the rope.3. **Image (c):** A triple pulley system (MA = 4) - The force \( T \) is distributed among four segments of the rope. Each image shows the force \( T \) acting on various points on the pulley system and the weight \( W \) of the load.#### Questions and Solutions:1. **(a) What would be the tension in newtons in the rope, assuming you pull straight up on the rope?** - **Answer:** 551.25 N2. **(b) What force in newtons must the ceiling supply?** - **Answer:** 1711.57 N ### Explanation:- **Tension Calculation:** - In an ideal pulley system, the tension in the rope is distributed based on the mechanical advantage. - For a system with MA = 4 (image (c)), the effective weight being lifted is divided by 4. - Given total weight (engine + pulley system) = mass \( \times \) gravity - \( \text{Total Mass} = 225\, \text{kg} + 5.90\, \text{kg} = 230.9\, \text{kg} \) - \( \text{Total Weight} (W) = 230.9\, \text{kg} \times 9.81\, \text{m/s}^2 = 2264.729\, \text{N} \) - Tension in each rope: - \( T = \frac{W}{4} = \frac{2264.729}{4} = 566.18\, \text{N} \) -

Name: ### Understanding Pulley Systems and Their Applications in Lifting###
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: ### Understanding Pulley Systems and Their Applications in Lifting#### Scenario:Suppose you used an ideal pulley of the type shown in image (c) in the figure below to support a car engine of mass 225 kg. The pulley system's mass is 5.90 kg.#### Figu