Suppose you know that f(8) = - 1, f'(8) = 10. Find the equation of the line tangent to the graph of 3 3 x + y + y³ − 360 = x² f(x) at x = 8. - The line passes through the point with slope The equation of the line will be

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Q: Consider the differential equation y'(x) = xeU – x.

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Q: e. lim f(1) f. lim f(r) 2 g. lim f(1)

A: e) -1+ is greater than -1, so we will take the second piece of the function

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A: This question is about application of complimentary angles

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Q: C- 16

A: when negative sign multiplied by negative then it becomes positive sign (-)×(-)=+

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A: As per the Bartleby guildlines we have to solve first three subparts and rest can be reposted...…