Suppose you invest $16,990.00 into an account earning an interest rate of 2.937% compounded continuously for 1 year(s) and thereafter earning an interest rate of 3.208% compounded weekly. How much money is in the account after 10 years? The amount in the account is $ Hint:

Q: How much would you need to deposit in an account now in order to have $2000 in the account in 15…

A: NOTE: Refresh your page if you can't see any equations. . here we have A=2000 future value)…

Q: Kellee deposits​ $5000 in a savings account with an interest rate of​ 0.9% compounded monthly. If…

A: From the given information, it is observed that Kellee deposited $5000 that is, P = $5000 with the…

Q: You deposit $500.00 every month into an account earning 2% interest compounded monthly. How much…

A: solution of the given problem is below...

Q: you deposit $5000 in an account earning 3% interest compounded monthly. how much will you have in…

A: We have given,

Q: You deposit $2000 in an account earning 2% interest compounded monthly. How much will you have in…

A: given, principal (P)=$2000           interest  rate (R)=2%= 2/100 =0.02     (for compounded monthly…

Q: You deposit $500.00 every month into an account earning 8% interest compounded monthly. How much…

A: In this question, concept of compound interest is applied. Compound Interest Compound interest is…

Q: You deposit $5000 in an account earning 3% interest compounded continuously. How much will you have…

A: See the attachment

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A:

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A:

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Q: Ms. Roberts decided to invest some money in an insurance company with an interest rate of 9%…

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Q: To have $4 000 in 6 years, how much do you need to invest now at 3.2% compounded monthly?

A:

Q: Mrs. Rees decides to invest $250 each month into an account that earns 1.8%/a compounded monthly.…

A: Mrs. Rees decides to invest $250 each monthrate=r= 1.8%/atime = 5 years

Q: If $6,000 is invested at 3% compounded monthly, what is the amount after 9 years? The amount after 9…

A: Invested amount P = $ 6,000               Interest rate  r = 3 %  = 3100 = 0.03…

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