Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment.Calculate the volume (in mL) of the 1.356 M stock NaOH solution needed to prepare 250.0 mL of 0.1199 M dilute NaOH solution. Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar. Glucose solutions are used to treat patients with low blood sugar.Suppose you prepare a glucose solution using the described procedure.• Step 1: Dissolve 240.6 g of glucose in enough water to make 500.0 mL of solution.• Step 2: Transfer 18.6 mL of the solution to a new flask and add enough water to make 250.0 mL of dilute solution.What is the concentration (in M) of the glucose solution at the end of the procedure?

M1 x V1 = M2 x V2 Where, M1 = Initial molarity; V1 = Initial volume M2 = Final molarity;…

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calculate the volume (in mL) of the 1.356 M stock NaOH solution needed to prepare 250.0 mL of 0.1199 M dilute NaOH solution.

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calculate the volume (in mL) of the 1.356 M stock NaOH solution needed to prepare 250.0 mL of 0.1199 M dilute NaOH solution.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: A student uses 239.3 mL of 0.4523 M sulfuric acid solution to titrate a quantity of sodium hydroxide…

A: Titration is a popular laboratory technique of quantitative analysis used to assess the…

Q: A 50.0 mL portion of a 0.360 M sucrose solution was diluted to 5.00 × 102 mL. What is the…

A: Given that, Initial concentration of sucrose M1=0.360M Initial volume of sucrose V1=50.0mL…

Q: 400.0 mL of a 0.455 M solution of NaCl is diluted to 900.0 mL. What is the new concentration of the…

A: Given, 400.0 mL of a 0.455 M solution of NaCl is diluted to 900.0 mLwe are asked to calculate the…

Q: To what volume should you dilute 30 mL of a 12 M H2SO4 solution to obtain a 0.17 M H2SO4 solution?…

Q: Determine the volume (in mL) of a 15.8 M HC2H3O2 stock solution must be used to prepare 775.0 mL of…

A: Dilution :- When a concentrated stock solution of molarity M1 and volume V1 is diluted by adding…

Q: 1. a. Which of the following solutions contains the greater mass? Briefly explain your answer or…

A: (a) Molarity and volume of MgCl2 is 1.60 L and 0.334 M Moles of MgCl2 =Molarity ×Volume=0.334 M×1.60…

Q: Suppose you are working with a NaOH stock solution but you need a solution with a lower…

Q: 600.0 mL of a 0.415 M solution of LiCl is diluted to 900.0 mL. What is the new concentration of the…

Q: Concentrated hydrochloric acid is 11.8 M. What volume of this solution should be used to prepare…

A: Given Initial Molarity of HCl( M1 ) = 11.8 M Final Molarity ( M2 ) = 0.477 M Final Volume ( V2 )…

Q: A chemist places 2.6428 g of NaCl in a 100 mL volumetric flask and adds water to the mark and calls…

A: The solution is given below -

Q: True or False? When 100.0 mL of 2.4 M hydrochloric acid is added to 500.0 mL of water, the…

A: molarity is defined as no of moles of solute devided by volume of solution in liter.

Q: What volume of 8.50 M NaCl solution needs to be diluted to produce 400.0 mL of 2.00 M NaCl solution?

A: In case of dilution of any electrolyte, the following relation is used : MiVi = MfVf

Q: What volume of a 6.8 M stock solution do you need to prepare 500. mL of a 3.4 M solution of MgSO4.…

A: Given: C1=Concentration of stock solution=6.8 MC2=Final Concentration =3.4 MV2=Final volume=500 ml…

Q: How much water ( in mL) must be added to a 4.01 M sulfuric acid solution to obtain 193.1 mL of 2.00…

Q: What mass of Fe(NO3)3 do you need to prepare 150.00 mL of 0.550 M solution? Make sure all of your…

A: Mole is a standard unit for measuring large quantities of very small entities such as…

Q: You are given 10.5 g of CaCl2, and you dissolve it into 2.47 L of H2O. What is the solution…

A: Given information: Mass of CaCl2 = 10.5 g Volume of solution = 2.47 L Volume of sucrose = 13.7 mL…

Q: You wish to make a 0.399 M nitric acid solution from a stock solution of 6.00 M nitric acid. How…

A: The process of dilution is defined as the process in which a solution with a lower concentration is…

Q: How many grams of KClKCl must be added to water to create 5.0 LL of an 0.020 MM KClKCl electrolyte…

Q: 400.0 mL of a 0.470 M solution of NaCl is diluted to 900.0 mL. What is the new concentration of the…

A: Initial volume (V1)= 400.0 mL = 0.400 L Initial molarity (M1) = 0.470 M Final volume (V2)=900.0 mL…

Q: Maria needs to dilute a stock solution of 16.0 M hydrochloric acid (HCI) for an experiment. If she…

A: We have a 5 mL of HCl solution having 16.0 M concentration...now, the final concentration of the…

Q: 400.0 mL of a 0.345 M solution of NaCl is diluted to 900.0 mL. What is the new concentration of the…

A: The correct answer is given below

Q: A student uses 29.3 mL of 0.482 M sulfuric acid solution to titrate an unknown quantity of sodium…

A: The titration between NaOH and H2SO4 is; H2SO4+2 NaOH→Na2SO4+2H2O The mole ratio between NaOH and…

Q: Calculate the volume (in mL) of a 1.205M stock NaOH solution needed to prepare 250.0 mL of a 0.1157M…

Q: Determine the volume (in mL) of a 13.8 M HNO3 stock solution must be used to prepare 325.0 mL of a…

A: From the stock solution we can prepare the desired solution by diluting the solution upto the given…

Q: 600.0 mL of a 0.420 M solution of LiCl is diluted to 900.0 mL. What is the new concentration of the…

A: To Solve this problem we use the formula M1V1 = M2V2 where , M1 = Molarity of initial Solution…

Q: the laboratory, a student dilutes 28.1 mL of a 8.85 M hydrobromic acid solution to a total volume of…

A: In this question, we will determine the concentration of dilute solution. You can see the whole…

Q: Suppose you need to prepare 10.0 mL of a 0.10 M NaOH solution. Calculate the volumes of 1 M NaOH…

Q: Suppose you are working with a NaOH stock solution but you need a solution with a lower…

A: Initial molarity of NaOH = M1 = 1.468 M Volume of NaOH needed to get the desired Concentration of…

Q: What volume of 0.275 M KMnO4 solution is needed to prepare 514. mL of 0.0270 M KMnO4? Enter your…

A: Molarity of a solution is defined as the number of moles of solute present in one litre of a…

Q: You mix 500.0 mL of 0.250 M iron(III) chloride solution with 375.0 mL of 0.350 M barium chloride…

A: Given : Molarity of iron (III) chloride (FeCl3) =0.250 M Volume of iron (III) chloride…

Q: 600.0 mL of a 0.470 M solution of LiCl is diluted to 900.0 mL. What is the new concentration of the…

Q: There is a 12 M aqueous HCl solution in the stock room, but a 1.0 M solution is required for an…

A: Given, a 12 M aqueous HCl solution in the stock.we are askesd to calculate the volume of stock…

Q: A particular solution of hydrochloric acid is 3.0 M. How many moles of hydrochloric acid are present…

Q: What is the concentration of methanol in a solution prepared by combining 7.97 mL of a 3.849 M…

Q: A chemist needs 13.46 mL of 1.17 M NaOH. What volume in mL of 3.89 M NaOH must be diluted in water…

A: Chemist needs 13.46 mL of the 1.17 M of NaOH solution. He do have stock solution as of 3.89 M ,we…

Q: A laboratory procedure calls for making 420.0 mL of a 1.3 M NaNO3 solution. What mass of NaNO3 (in…

A: The molarity(M) of a solution can be represented as the number of moles of solute(n) found in one…

Q: The three drawings below represent aqueous ionic solutions. Solution A has a total volume of 25 mL,…

A: Concentration terms.MOLARITYMolarity of the solution is basically the number of moles of solute…

Q: A chemist dissolves 13.5 g of NaCl in enough water to make a 2500 mL solution. Calculate the…

A: Given, Mass of NaCl = 13.5 g Note: 1000 mL = 1 L Volume of the solution = 2500 mL = 2.5 L Molarity…

Q: 19.3 mL of a 2.8 M solution of lithium hydroxide is used to prepare a solution with a concentration…

A: Given : concentration of initial solution = 2.8 M volume of initial solution = 19.3 mL And…

Q: concentration

Q: 400.0 mL of a 0.500 M solution of NaCl is diluted to 900.0 mL. What is the new concentration of the…

A: Given: Note: (1L = 1000mL)

Q: 400.0 mL of a 0.470 M solution of NaCl is diluted to 900.0 mL. What is the new concentration of the…

A: We can determine the new concentration of the solution after diluted NaCl solution by using dilution…

Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment.
Calculate the volume (in mL) of the 1.356 M stock NaOH solution needed to prepare 250.0 mL of 0.1199 M dilute NaOH solution.

Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar. Glucose solutions are used to treat patients with low blood sugar.
Suppose you prepare a glucose solution using the described procedure.
• Step 1: Dissolve 240.6 g of glucose in enough water to make 500.0 mL of solution.
• Step 2: Transfer 18.6 mL of the solution to a new flask and add enough water to make 250.0 mL of dilute solution.
What is the concentration (in M) of the glucose solution at the end of the procedure?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

In an experiment, a student combines 75.0 mL of a 0.190 M iron (III) chloride solution with 125.0 mL of a 0.240 M sodium carbonate solution. What is the theoretical yield of sodium chloride (in grams)?
500.0 mL of a 0.375 M solution of LiBr is diluted to 700.0 mL. What is the new concentration of the solution?
What volume (in mL) of 2.85 M potassium sulfate solution would contain 30.8 g of solute? Enter only the numerical answer in the box. Give 3 sig figs in your answer.
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calculate the volume (in mL) of the 1.100 M stock NaOH solution needed to prepare 250.0 mL of 0.1230 M dilute NaOH solution.
Suppose that 2.89 L of 6.75 M potassium carbonate is added to 1.38 L of 1.57 M magnesium nitrate. What is the total concentration of ions in solution after the reaction goes to completion? (Do not include units in your answer. If you round during your calculation make sure to keep at least 3 decimal places. Report your answer to 1 decimal place.)
You add 25.0 mL dionized water to 60.0 mL of 0.450 M potassium cyanate. Calculate the molarity of the resulting solution.
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calculate the volume (in mL) of the 1.048 M stock NaOH solution needed to prepare 250.0 mL of 0.1410 M dilute NaOH solution.
A student in a lab takes 16.0 M aqueous stock solutions and dilutes it in a 500 mL volumetric flask with deionized water. After that the student takes 10 mL of the resulting diluted solution, and further dilutes it to 25.0 mL in a test tube. The student did so with the intention of making 25.0 mL of a 0.750 solution. In order to make the final 25.0 mL solution, how much stock solution did the student need to add to the 500 mL volumetric flask?
you need to make 150.0 mL of a 0.10 M NaCl solution. You have solid NaCl, and your lab partner has a 2.5 M NaCl solution. Explain how you each independently make the solution you need.
Please help
You mix 500.0 ml of 0.250 M iron(III) chloride solution with 225.0 mL of 0.350 M barium chloride solution. Assuming the volumes are additive, what is the molarity of chloride ion in the mixture.
400.0 mL of a 0.385 M solution of NaCl is diluted to 900.0 mL. What is the new concentration of the solution?